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2 years ago

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1.6.PS-25

1 answer:

gtnhenbr [62]2 years ago

8 0

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Question Two please help

lana66690 [7]

Answer:

The similarity statement is RTS and ACB. Other options are correct

8 0

2 years ago

If square ABCD with side length of 7 units is reflected over the line y=x, what is length A'B'?

Art [367]

Answer:

7

Step-by-step explanation:

Reflection is a rigid transformation, so the side length does not change.

A'B' = 7

5 0

3 years ago

Solve the following absolute value equations. Show the solution set and check your answers. |0.3-3/5k|-0.4=1.2

9966 [12]

Answer:

**The equation is not clear, so I have provided both options**

<h3><u>Option 1</u></h3>

$\left|0.3-\dfrac{3}{5}k\right|-0.4=1.2$

$\implies \left|0.3-\dfrac{3}{5}k\right|=1.6$

<u>Solution 1</u>

$\implies 0.3-\dfrac{3}{5}k=1.6$

$\implies -\dfrac{3}{5}k=1.3$

$\implies k=-\dfrac{13}{6}$

<u>Solution 2</u>

$\implies -(0.3-\dfrac{3}{5}k)=1.6$

$\implies -0.3+\dfrac{3}{5}k=1.6$

$\implies \dfrac{3}{5}k=1.9$

$\implies k=\dfrac{19}{6}$

<h3><u>Option 2</u></h3>

$\left|0.3-\dfrac{3}{5k}\right|-0.4=1.2$

$\implies \left|0.3-\dfrac{3}{5k}\right|=1.6$

<u>Solution 1</u>

$\implies 0.3-\dfrac{3}{5k}=1.6$

$\implies -\dfrac{3}{5k}=1.3$

$\implies -3=6.5k$

$\implies k=-\dfrac{6}{13}$

<u>Solution 2</u>

$\implies -(0.3-\dfrac{3}{5k})=1.6$

$\implies -0.3+\dfrac{3}{5k}=1.6$

$\implies \dfrac{3}{5k}=1.9$

$\implies 3=9.5k$

$\implies k=\dfrac{6}{19}$

6 0

1 year ago

Lance paid 6% sales tax on a $30 game what total amount did Lance pay?

inysia [295]

The answer should be $31.80.
Hope this helped!!!:)

3 0

3 years ago

Read 2 more answers

How to find x please help

o-na [289]

You know the adjacent and you need to find the opposite, so you would use tangent. Your equation would look like this; tan 26°= x/28. You would need to multiply both sides by 28 to simplify it to this; 28*tan 26°= x
Solving this, you would get an answer of 13.7

6 0

3 years ago