Proof:
The slope of (0,0) to (1,0) is undefined (the denominator is 0). Same with (1,1) to (0,1).
The slope of (0,0) to (0,1) and (0,1) to (1,1) is 0.
There are two parallel lines, and the slope are negative reciprocals of each other, meaning they're perpendicular.
The distance of the points are all 1.
Therefore, it fits the requirements of a square.
Answer:
y = √(x - 3)
Step-by-step explanation:
The graph shown has exactly the same shape as does the graph of y = √x, EXCEPT that the entire graph of y = √x has been translated 3 units to the right. Thus, the function describing this graph is y = √(x - 3).
Answer:
A. -2^X, B. 2^X, C. 2^(X+2), D. -2^(X+2)
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
2/4 is equal to 1/2
3/6 is also equal to 1/2
thus the two fractions are equivalent
Answer:
A. G'(5) = 20
B. G'(5) = -1
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Functions
- Function Notation
<u>Calculus</u>
Derivatives
Derivative Notation
Derivative Rule [Product Rule]:
Derivative Rule [Quotient Rule]:
Step-by-step explanation:
<u>Step 1: Define</u>
[Given] F(5) = 4, F'(5) = 4, H(5) = 2, H'(5) = 3
[Given] A. G(z) = F(z) · H(z)
[Given] B. G(w) = F(w) / H(w)
[Find] G'(5)
<u>Step 2: Differentiate</u>
A. G(z) = F(z) · H(z)
- [Derivative] Product Rule: G'(z) = F'(z)H(z) + F(z)H'(z)
B. G(w) = F(w) / H(w)
- [Derivative] Quotient Rule: G'(w) = [F'(w)H(w) - F(w)H'(w)] / H²(w)
<u>Step 3: Evaluate</u>
A. G'(5)
- Substitute in <em>x </em>[Function]: G'(5) = F'(5)H(5) + F(5)H'(5)
- Substitute in function values: G'(5) = 4(2) + 4(3)
- Multiply: G'(5) = 8 + 12
- Add: G'(5) = 20
B. G'(5)
- Substitute in <em>x</em> [Function]: G'(5) = [F'(5)H(5) - F(5)H'(5)] / H²(5)
- Substitute in function values: G'(5) = [4(2) - 4(3)] / 2²
- Exponents: G'(5) = [4(2) - 4(3)] / 4
- [Brackets] Multiply: G'(5) = [8 - 12] / 4
- [Brackets] Subtract: G'(5) = -4 / 4
- Divide: G'(5) = -1
Topic: AP Calculus AB/BC (Calculus I/II)
Unit: Derivatives
Book: College Calculus 10e