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nikitadnepr [17]

3 years ago

13

Which of the following is the last step in problem solving? A. Understand the problem. B. Check your answers and present the sol

ution. O C. Gather your resources. O D. Come to an answer.

1 answer:

almond37 [142]3 years ago

7 0

B - check your answers and present the solution

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In a sample of 150 cars, 18 cars failed a safety inspection. The sampling method had a margin of error of 0.02

mestny [16]

Answer:

(Lower limit, Upper limit) = (0.10, 0.14)

(Lower limit, Upper limit) = (10%, 14%)

Step-by-step explanation:

Total number of cars = 150

Cars that failed the safety inspection = 18

The proportion is given by

p = 18/150

p = 0.12

p = 12%

The confidence interval is given by

p ± margin of error

Where margin of error is 0.02

0.12 ± 0.02

Lower limit = 0.12 - 0.02

Lower limit = 0.10

Lower limit = 10%

Upper limit = 0.12 + 0.02

Upper limit = 0.14

Upper limit = 14%

(Lower limit, Upper limit) = (0.10, 0.14)

(Lower limit, Upper limit) = (10%, 14%)

7 0

3 years ago

PLEASE HELP I’LL MAKE YOU THE BRAINIEST <br> find the area of the trapezoid to the nearest tenth

murzikaleks [220]

Answer:

2.7m

Step-by-step explanation:

1.0m

0.5m

+1.2m

2.7m - answer

5 0

2 years ago

Exponetial funtion is

r-ruslan [8.4K]

An exponential function in mathematics is an exponential function is a function of the form where b is a positive real number, and in which the argument x occurs as an exponent. So its a function whose value is a constant raised to the power of the argument, especially the function where the constant is e.

4 0

3 years ago

6= 2(y+2) i need help on this

vitfil [10]

Y = 1
This the answer just trust

8 0

2 years ago

5. Find the general solution to y'''-y''+4y'-4y = 0

CaHeK987 [17]

For any equation,

$a_ny^(n)+\dots+a_1y'+a_0y=0$

assume solution of a form, $e^{yt}$

Which leads to,

$(e^{yt})'''-(e^{yt})''+4(e^{yt})'-4e^{yt}=0$

Simplify to,

$e^{yt}(y^3-y^2+4y-4)=0$

Then find solutions,

$\underline{y_1=1}, \underline{y_2=2i}, \underline{y_3=-2i}$

For non repeated real root y, we have a form of,

$y_1=c_1e^t$

Following up,

For two non repeated complex roots $y_2\neq y_3$ where,

$y_2=a+bi$

and,

$y_3=a-bi$

the general solution has a form of,

$y=e^{at}(c_2\cos(bt)+c_3\sin(bt))$

Or in this case,

$y=e^0(c_2\cos(2t)+c_3\sin(2t))$

Now we just refine and get,

$\boxed{y=c_1e^t+c_2\cos(2t)+c_3\sin(2t)}$

Hope this helps.

r3t40

5 0

4 years ago