Hello :
x²-8x+15 = (x-3)(x-5)
<span>h(x) = f(x) ÷g(x) = (x-3)(x-5)/(x-3)= x-5</span>
If <em>x</em>² + <em>y</em>² = 1, then <em>y</em> = ±√(1 - <em>x</em>²).
Let <em>f(x)</em> = |<em>x</em>| + |±√(1 - <em>x</em>²)| = |<em>x</em>| + √(1 - <em>x</em>²).
If <em>x</em> < 0, we have |<em>x</em>| = -<em>x</em> ; otherwise, if <em>x</em> ≥ 0, then |<em>x</em>| = <em>x</em>.
• Case 1: suppose <em>x</em> < 0. Then
<em>f(x)</em> = -<em>x</em> + √(1 - <em>x</em>²)
<em>f'(x)</em> = -1 - <em>x</em>/√(1 - <em>x</em>²) = 0 → <em>x</em> = -1/√2 → <em>y</em> = ±1/√2
• Case 2: suppose <em>x</em> ≥ 0. Then
<em>f(x)</em> = <em>x</em> + √(1 - <em>x</em>²)
<em>f'(x)</em> = 1 - <em>x</em>/√(1 - <em>x</em>²) = 0 → <em>x</em> = 1/√2 → <em>y</em> = ±1/√2
In either case, |<em>x</em>| = |<em>y</em>| = 1/√2, so the maximum value of their sum is 2/√2 = √2.
The rephrased statement for Kun's proof is: A. In quadrilateral ABCD, if AB ≅ DC & AD ≅ BC, then AB║DC & AD║BC.
<h3>What is a Parallelogram?</h3>
A parallelogram is a quadrilateral that has two opposite sides that are congruent to each other and are also parallel to each other.
This means that if two pairs of opposite sides of a quadrilateral are congruent and parallel, then it is a parallelogram.
Rephrasing Kun's statement in his proof will therefore be: A. In quadrilateral ABCD, if AB ≅ DC & AD ≅ BC, then AB║DC & AD║BC.
Learn more about a parallelogram on:
brainly.com/question/12167853
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Answer:
0.75x
Step-by-step explanation:
Given that :
Discount rate= 25%
Original price = x
Discounted price of jacket :
(100 - discount rate)% * original price
(100 - 25)% * x
75% * x
0.75x
Answer:
62/100 multiplied by 650 which is 403 fruits left
