Answer:
The constant force exerted on the ball by the wall is 119.68 N.
Step-by-step explanation:
Consider the provided information.
It is given that the mass of the ball is m = 2.2 kg
The initial velocity of the ball towards left is 7.4 m/s
So the momentum of the ball when it strikes is = 
The final velocity of the ball is -6.2 m/s
So the momentum of the ball when it strikes back is = 
Thus change in moment is: 
The duration of force exerted on the ball t = 0.25 s
Therefore, the constant force exerted on the ball by the wall is:
Hence, the constant force exerted on the ball by the wall is 119.68 N.
Answer:
Step-by-step explanation:
The equation 
represents the discriminant of a quadratic. It is the part taken from under the radical in the quadratic formula.
For any quadratic:
- If the discriminant is positive, or greater than 0, the quadratic has two solutions
- If the discriminant is equal to 0, the quadratic has one distinct real solution (the solution is repeated).
- If the discriminant is negative, or less than 0, the quadratic has zero solutions
In the graph, we see that the equation intersects the x-axis at two distinct points. Therefore, the quadratic has two solutions and the discriminant must be positive. Thus, we have 
.
But x must be a natural number, so the answer is
.
Radius of curvature = 10'
Diameter of circle = 2 * 10' = 20'
height of segment = 2'
Let semi-chord be x.
Then by the intersecting chord property,
2*(20-2)=x^2
x^2=36
x=sqrt(36)=6
=>
chord=2x=2*6=12'
Answer:
No Solutions
Step-by-step explanation:
for |4x -3| + 10 < 2
|4x - 3| < -8
Not possible since absolute value is positive
