How do you say hi in chamoru?

Find the value of x if the points (x,5) and (3,7) lie on the line whose slope is 4/7

muminat

Answer:

x = -4

Step-by-step explanation:

Write and solve an equation in which the slope from the definition of slope is on the left side and the given slope, 4/7, is on the right side:

7 - 5 4

m = ---------- = --------

3 - x 7

Simplifying with the aim to find the value of x:

2(7) = 4(3 - x), or 7 = 3 - x. Then x = -4.

6 0

3 years ago

Explanation A random sample of 100 observations from a normally distributed population possesses a mean equal to 83.2 and a stan

Olenka [21]

Answer:

The 95% confidence interval would be given by (81.933;84.467)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=83.2$ represent the sample mean

$\mu$ population mean (variable of interest)

s=6.4 represent the sample standard deviation

n=100 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=100-1=99$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,99)".And we see that $t_{\alpha/2}=1.98$

Now we have everything in order to replace into formula (1):

$83.2-1.98\frac{6.4}{\sqrt{100}}=81.933$

$83.2+1.98\frac{6.4}{\sqrt{100}}=84.467$

So on this case the 95% confidence interval would be given by (81.933;84.467)

7 0

3 years ago

Susan has 10 pockets and 44 dollar bills. She wants to arrange the money so that there are a different number of dollars in each

levacccp [35]

Answer:

No

Step-by-step explanation:

The answer is no because no pocket can be empty and there isn't enough money to satisfy the condition. At least, one dollar must be stored in each pocket but the number (integer) of dollars in each pocket is different.

Let's store the minimum amount of dollars in the pockets while satisfying the condition. Place 1 dollar in the first pocket. The second pocket must have 2 dollars (it can't be 1 dollar, it must be a different number of dollars). The third pocket must have third dollars.

Repeating this process, the ninth pocket must have 9 dollars. At this moment, we have arranged 1+2+3+4+5+6+7+8+9=45 dollars in our pockets. But we only had 44 dollars! Plus, the tenth pocket is still empty.

If you store more dollars on the first, second, nth pockets, you will just run out of money more quickly than in our process above. so it's impossible to arrange the money in such way.

8 0

3 years ago

The probability that Barry Bonds hits a home run on any given at-bat is 0.16, and each at-bat is independent.

serious [3.7K]

Answer:

a) 0.0797 = 7.97% probability that the next home run will be on his fifth at-bat.

b) The expected number of at-bats until the next home run is 6.25.

Step-by-step explanation:

For each at bat, there are two possible outcomes. Either it is a home run, or it is not. The probability of an at bat resulting in a home run is independent of any other at-bat, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that Barry Bonds hits a home run on any given at-bat is 0.16

This means that $p = 0.16$

Part A: What is the probability that the next home run will be on his fifth at-bat?

0 on his next 4(P(X = 0) when n = 4)

Home run on his 5th at-bat, with 0.16 probability. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{4,0}.(0.16)^{0}.(0.84)^{4} = 0.49787136
$

0.49787136 *0.16 = 0.0797.

0.0797 = 7.97% probability that the next home run will be on his fifth at-bat.

Part B: What is the expected number of at-bats until the next home run?

The expected number of trials for n successes is given by:

$E = \frac{n}{p}$

In this question, $n = 1, p = 0.16$ . So

$E = \frac{1}{0.16} = 6.25$

The expected number of at-bats until the next home run is 6.25.

6 0

2 years ago

The average cost of printing a book in a publishing company is c(x) =, <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B5.5x%2Bk%7

Bogdan [553]

To find K, we must use the fact that
on the day 200 books were printed
the average cost was $ 9 per book.
Thus, substituting the values, we have:
c (x) = (5.5x + k) / (x)
9 = (5.5 (200) + k) / (200)
Clearing K
(200) * 9 = 5.5 (200) + k
k = (200) * 9 - 5.5 * (200)
k = 700
answer
the value of the constant k is 700

3 0

3 years ago

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How do you say hi in chamoru?​

How do you say hi in chamoru?