Table 1: The horizontal pulling forces (F) and resulting acceleration (a) for the cart.
The cart experiences no motion when there is 0.1 N of horizontal force, so F=0 in this case. When one uses Newton's Second Law to find the acceleration caused by each force, it becomes clear that every row in the chart represents a horizontal force of approximately F=20 N. The best fit for the missing value is F=-30N.
Answer:
it retains water
Explanation:
clay soil is a hard kind of soil, since its hard its not loose. sand is what drains quickly, clay drains slowly and retains water for much longer than sand does.
Answer:
this mutation may change the open reading frame of the resulting RNA sequence and its final product, which is a protein in the case that this gene is used to synthesize a messenger RNA (mRNA) sequence
Explanation:
During the transcription, a region of DNA named 'gene' is used as template to produce an RNA molecule, typically a primary transcript of mRNA (pre-mRNA). Subsequently, this pre-mRNA suffers a process named RNA processing in order to generate a mature mRNA which is finally used to create a protein by a process called translation. If a deletion occurs during transcription, it may change the open reading frame (ORF) of the resulting mRNA when the mutation occurs in an exon of the protein-coding gene (i.e., occurs a frameshift mutation), while this deletion may not have any effect if it is localized within the introns which are removed during RNA processing. A frameshift mutation will change the amino acids that are added to the nascent polypeptide chain during translation.
Answer:
Cactus (Cacti) Joshua Tree (Trees), Desert Lily (Flowers)
Explanation:
The producers I have mentioned are all plants and produce either food or oxygen.
Answer:
population = 600
heterozygotes = 2pq
The homozygous recessive percentage = 
q = 0.1
Solve for q:
∴ q = 
∴ q = 
∴ q = 0.316
solve for p:
for p + q = 1,
thus p = 1 – q = 1 – 0.316 = 0.684
The heterozygotes = 2pq
2pq = 2 x 0.316 x 0.684 = 0.432
600 x 0.432 = 259.2 = 259
so, the population reaches Hardy Weinberg equilibrium, 259 of indviduals should be heterozygous for this trait.
Hence, the correct answer is 259
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