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Dovator [93]
2 years ago
10

What is the range of the function

Mathematics
1 answer:
alexandr1967 [171]2 years ago
7 0

Answer: Choice B

Range = {-3, 1, 5}

============================================

Explanation:

The domain is the set of all possible input x values. The range is the set of all possible y outputs.

Plug in each x value from the domain, one at a time, to get its corresponding range y value.

--------------------

Start with x = -3

f(x) = 2x+3

f(-3) = 2(-3)+3

f(-3) = -6+3

f(-3) = -3

So -3 is in the range.

--------------------

Move onto x = -1

f(x) = 2x+3

f(-1) = 2(-1)+3

f(-1) = -2+3

f(-1) = 1

1 is also in the range

--------------------

Finally plug in x = 1

f(x) = 2x+3

f(1) = 2(1)+3

f(1) = 2+3

f(1) = 5

The value 5 is the final value in the range.

--------------------

All of those values form the set {-3, 1, 5} which is the complete range.

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STatiana [176]

Sum of interior angles of a △ = 180°

∴ ∠T + ∠V + ∠U = 180°

⇒ 37° + 63° + X° = 180°

⇒ X° + 100 = 180°

⇒ X° = 180° - 100°

⇒ X° = 80° (D).

5 0
3 years ago
Two cars are side by side. One is 3.9 meters long. The other is 6% shorter. How long is the second car?
GrogVix [38]

Answer:

3.66meters long

Step-by-step explanation:

since it's 6% shorter you calculate 3.9 times .94(which is basically 94 percent) which gives you 3.66 meters long

7 0
2 years ago
Common Core Algebra 1 - MAZINS ATC
katen-ka-za [31]
200=x-4 original equation
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x=204 symmetric property
4 0
3 years ago
Suppose that X has a Poisson distribution with a mean of 64. Approximate the following probabilities. Round the answers to 4 dec
o-na [289]

Answer:

(a) The probability of the event (<em>X</em> > 84) is 0.007.

(b) The probability of the event (<em>X</em> < 64) is 0.483.

Step-by-step explanation:

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 64.

The probability mass function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0, 1, 2, ...

(a)

Compute the probability of the event (<em>X</em> > 84) as follows:

P (X > 84) = 1 - P (X ≤ 84)

                =1-\sum _{x=0}^{x=84}\frac{e^{-64}(64)^{x}}{x!}\\=1-[e^{-64}\sum _{x=0}^{x=84}\frac{(64)^{x}}{x!}]\\=1-[e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{84}}{84!}]]\\=1-0.99308\\=0.00692\\\approx0.007

Thus, the probability of the event (<em>X</em> > 84) is 0.007.

(b)

Compute the probability of the event (<em>X</em> < 64) as follows:

P (X < 64) = P (X = 0) + P (X = 1) + P (X = 2) + ... + P (X = 63)

                =\sum _{x=0}^{x=63}\frac{e^{-64}(64)^{x}}{x!}\\=e^{-64}\sum _{x=0}^{x=63}\frac{(64)^{x}}{x!}\\=e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{63}}{63!}]\\=0.48338\\\approx0.483

Thus, the probability of the event (<em>X</em> < 64) is 0.483.

5 0
3 years ago
Solve the inequality
ollegr [7]

Answer:

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Step-by-step explanation:

Solve the bracket first (9-18n)

add the n together (-15n)

add the 9 and the -96 together (-105)

Divide 105 and 15n (7)

n < 7

Have a good day :)

4 0
3 years ago
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