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2 years ago

Which of the following expressions is not equal to X^3?

Mathematics

1 answer:

Musya8 [376]2 years ago

6 0

Answer:

D. x. x^7 . x^-4

Step-by-step explanation:

A. X^5 . X^-4 .X^2=X^(5-4+2)= X^3

B. X^-2 .X^9 .x^-4=X^(-2+9-4)= X^3

C.x^0 . x^10 . x^-7=X^(0+10-7)= X^3

D. x. x^7 . x^-4=X^(1+7-4)= X^4

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Average movie prices in the United States are, in general, lower than in other countries. It would cost 80.95 to buy three ti

densk [106]

Answer:

In Japan a movie ticket has a price of 17.99, and in Switzerland has a price of 13.49.

Step-by-step explanation:

Step 1.

Let x be the price of a movie ticket in Japan
Let y be the price of a movie ticket in Switzerland

Step 2.

According with the description:

$3x+2y=80.95$ , (It would cost 80.95 to buy three tickets in Japan + two tickets in Switzerland).

$2x+3y=76.45$ , (Three tickets in Switzerland + two tickets in Japan would cost 76.45).

Step 3.

The two equations of step 2 can be used to solve both x and y. From the first equation, solving x:

$x=\frac{80.95-2y}{3}$ .

Step 4.

Replacing x in the second equation:

$2*\frac{80.95-2y}{3}+3y=76.45$ .

Solving for y (price in Switzerland):

$y=13.49$

Step 5.

Using the found value of y to solve for x (price in Japan):

$x=\frac{80.95-2(13.49)}{3}=17.99$

Step 6.

Then it is possible to check that:

$3(17.99)+2(13.49)=80.95$

$2(17.99)+3(13.49)=76.45$

5 0

2 years ago

PLEASE HELPP!!! explain your reasoning!

Luden [163]

Answer:

yes

Step-by-step explanation:

for each sale price, there is a $5 deduction from the original price

5 0

2 years ago

Find the area of a rectangle that is 4-inches-wide and 15-inches-long.

Ratling [72]

Answer:

the area of a rectangle that is 4-inches-wide and 15-inches-long =15*4=60 square inches

3 0

2 years ago

Read 2 more answers

Prove identity trigonometric equation

irina [24]

Explanation:

The given equation is False, so cannot be proven to be true.

Perhaps you want to prove ...

$2\tan{x}=\dfrac{\cos{x}}{\csc{(x)}-1}+\dfrac{\cos{x}}{\csc{(x)}+1}$

This is one way to show it:

$2\tan{x}=\cos{(x)}\dfrac{(\csc{(x)}+1)+(\csc{(x)}-1)}{(\csc{(x)}-1)(\csc{(x)}+1)}\\\\=\cos{(x)}\dfrac{2\csc{(x)}}{\csc{(x)}^2-1}=2\cos{(x)}\dfrac{\csc{x}}{\cot{(x)}^2}=2\dfrac{\cos{(x)}\sin{(x)}^2}{\cos{(x)}^2\sin{(x)}}\\\\=2\dfrac{\sin{x}}{\cos{x}}\\\\2\tan{x}=2\tan{x}\qquad\text{QED}$

We have used the identities ...

csc = 1/sin

cot = cos/sin

csc^2 -1 = cot^2

tan = sin/cos

4 0

2 years ago

Suppose that the IQs of university A's students can be described by a normal model with mean 150150 and standard deviation 77 p

NeX [460]

Answer:

The probability that the student's IQ is at least 140 points is of 55.17%.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

University A: $\mu = 150, \sigma = 77$