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2 years ago

HELPPPPP MEEEEEE Which one is not a solution to y = 3x - 5? A. (0, –5) B. (– 1, – 2) C. (5/3, 0) D. (2, 1)

Mathematics

1 answer:

nignag [31]2 years ago

7 0

Answer:

Step-by-step explanation:

Let's examine the individual things

A. x=0 --> y=3.0-5=-5 True

B. x=-1 --> y=3.(-1)-5=-8 False

C. x=5/3 -->y=3(5/3)-5=0 True

D. x=2 --> y=3.2-5=1 True

Answer is B.

You don't understand, you can ask me :)

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) use the midpoint rule with m= 4 and n = 2 to estimate the value of

Aneli [31]

What is the complete question?

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2 years ago

HURRY PLS!! TEST!!!!

stich3 [128]

Answer:

y=-5x+19

Step-by-step explanation:

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5 0

1 year ago

An SRS of 350 high school seniors gained an average of x¯=21 points in their second attempt at the SAT Mathematics exam. Assume

Lynna [10]

Answer:

a) $21-2.58\frac{52}{\sqrt{350}}=13.83$

$21+2.58\frac{52}{\sqrt{350}}=28.17$

So on this case the 99% confidence interval would be given by (13.83;28.17)

b) $ME=2.58\frac{52}{\sqrt{350}}=7.17$

c) $ME=2.58\frac{52}{\sqrt{100}}=13.42$

d) D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part a

$\bar X=21$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=52$ represent the population standard deviation

n=350 represent the sample size

99% confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$

Now we have everything in order to replace into formula (1):

$21-2.58\frac{52}{\sqrt{350}}=13.83$

$21+2.58\frac{52}{\sqrt{350}}=28.17$

So on this case the 99% confidence interval would be given by (13.83;28.17)

Part b

The margin of error is given by:

$ME=2.58\frac{52}{\sqrt{350}}=7.17$

Part c

The margin of error is given by:

$ME=2.58\frac{52}{\sqrt{100}}=13.42$

Part d

As we can see when we reduce the sample size we increase the margin of error so the best option for this case is:

D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

6 0

2 years ago

If f(x)=5x^3 and g(x)=x+1, find (f•g)(x)

alukav5142 [94]

Hello from MrBillDoesMath!

Answer:

5 x^3 + 15 x^2 + 15 x + 5 , none of the provided choices

Discussion:

f(x) = 5 x^3

g(x) = x+ 1

(f•g)(x) =

f(g(x)) =

f(x+1) =

5 * (x+1)^3 =

5 x^3 + 15 x^2 + 15 x + 5

which is none of the provided answers.

Thank you,

MrB

5 0

2 years ago

HELLPP PLEASE :) THIS IS HARD BRAINLIEST!

lorasvet [3.4K]

Answer:

1).B

2).A

3).D

4).B

5).C

6).D

7).D

8).B

9).C

10). I believe it is A

Step-by-step explanation:

I'm sorry, i do not know how to explain this, I hope I helped you in some way and I hope these answers work for you :)

7 0

2 years ago