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saw5 [17]
3 years ago
14

How many solutions are there to the equation 12x+6=5x

Mathematics
1 answer:
Alenkinab [10]3 years ago
4 0

Answer:

One solution; x = -\frac{6}{7}

Step-by-step explanation:

12x + 6 = 5x

12x - 5x = -6

7x = -6

x = -\frac{6}{7}

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Find the range and interquartile range for the data represented by the box plot.
Anarel [89]

<u>Given</u>:

Given that the data are represented by the box plot.

We need to determine the range and interquartile range.

<u>Range:</u>

The range of the data is the difference between the highest and the lowest value in the given set of data.

From the box plot, the highest value is 30 and the lowest value is 15.

Thus, the range of the data is given by

Range = Highest value - Lowest value

Range = 30 - 15 = 15

Thus, the range of the data is 15.

<u>Interquartile range:</u>

The interquartile range is the difference between the ends of the box in the box plot.

Thus, the interquartile range is given by

Interquartile range = 27 - 18 = 9

Thus, the interquartile range is 9.

3 0
3 years ago
Read 2 more answers
Worth five points! it doesnt tell me if what answer is right but if i get 75% or up i will mark the first person who answered wi
Mrrafil [7]

Answer:

A

Step-by-step explanation:

Remarks

  • The given angle is an exterior angle.
  • It's value is 46 degrees.    
  • An exterior angle is the sum of the two remote angles. (A remote angle is one that is not supplementary  to the given exterior angle.

Solution

  • 46 = <u + <t
  • <t = 29
  • 46 = <u + 29               Subtract 29 from both sides.
  • 46 - 29 = <u
  • <u = 17 degrees
4 0
3 years ago
A farmer collected 12 dozen eggs from her chickens. She sold 5/6 of the eggs at the farmers' market, and gave the rest to friend
KATRIN_1 [288]
She gave them 24 dozens. To answer, you multiply 12x12 which equals 144. Then divide that by 6 and you get 24
5 0
3 years ago
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Cube-shaped boxes will be loaded into the cargo hold of a truck. The cargo hold of the truck is in the shape of a rectangular pr
Mrrafil [7]
Solve each problem. Volume of a Box A piece of sheet metal is 2.5 times as long as it is wide. It is to be made into a box with an open top by cutting 3 -inch squares from each corner and folding up the sides, as shown at the top of the next page. Let x
represent the width of the original piece of sheet metal. (a) Represent the length of the original piece of sheet metal in terms of x.
(b) What are the restrictions on x?
(c) Determine a function V
that represents the volume of the box in terms of x
(d) For what values of x
(that is, original widths) will the volume of the box be between 600 and 800 cubic inches? Determine the answer graphically, and give values to the nearest tenth of an inch
3 0
2 years ago
Please help me!! Will get brainliest!
makvit [3.9K]
Completing the square follows the principle of taking a x^{2} +bx+c and converting it into (x+ \frac{b}{2})^2+d where d is the 'correctional number' as I like to call it - i.e. the number that converts the expanded bracket into the +c, since the expanded bracket will give us a x^{2} +b.

In this case, 2/2=1 so we have the first part: (w+1)^2.
Expanding this gives us w^2+2w+1. We need c to be 9, so we can just add 8.
Putting this together:

w^2+2w+9=(w+1)^2+8

Now we can solve it more easily.
Rearranging:
(w+1)^2=-8 \\ w+1= +-\sqrt{-8} = +-\sqrt{8}i=+-2 \sqrt{2}i   \\ \boxed{w=-1+ 2\sqrt{2}i\ or\ -1-2 \sqrt{2}i  }
5 0
3 years ago
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