3 I believe because I did it differently
Answer:
17822
Step-by-step explanation:
The number that are divisible by 7 between 30 and 500 are as follows :
35, 42,49,.....,497
It will form an AP with first term, a = 35 and common difference, d = 7
Let there are n terms in the AP.
nth term of an AP is given by :

Putting all the values,

Now, the sum of n terms of an AP is given by :
![S_n=\dfrac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cdfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Putting all the values,
![S_n=\dfrac{67}{2}[2(35)+(67-1)7]\\\\S_n=17822](https://tex.z-dn.net/?f=S_n%3D%5Cdfrac%7B67%7D%7B2%7D%5B2%2835%29%2B%2867-1%297%5D%5C%5C%5C%5CS_n%3D17822)
Hence, the sum of the numbers that are divisible by 7 between 30 and 500 is 17822.
Answer:
(-2,9) ,(4,-3)
Step-by-step explanation:
Given the expression 2x+y=5
We are required to look for values of x and y such that when substituted into the given expression will result in the number 5
The Pairs are (-2,9) ,(4,-3)
Let us plug in the values to check
1. (-2,9)
2(-2)+9=5
-4+9=5
5=5 true
2. (4,-3)
2(4)+(-3)=5
8-3=5
5=5 true
That answer is 180. The formula is a=bh1/2