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3 years ago

I need help with fractions

Mathematics

2 answers:

goldenfox [79]3 years ago

8 0

Answer:

what do u need help with

Step-by-step explanation:

bezimeni [28]3 years ago

5 0

Answer:

Step-by-step explanation:

You might be interested in

Solve 4 cos2x-3 = 0 for all real values of x.

vichka [17]

4 cos² x - 3 = 0

4 cos² x = 3

cos² x = 3/4

cos x = ±(√3)/2

Fixing the squared cosine doesn't discriminate among quadrants. There's one in every quadrant

cos x = ± cos(π/6)

Let's do plus first. In general, cos x = cos a has solutions x = ±a + 2πk integer k

cos x = cos(π/6)

x = ±π/6 + 2πk

Minus next.

cos x = -cos(π/6)

cos x = cos(π - π/6)

cos x = cos(5π/6)

x = ±5π/6 + 2πk

We'll write all our solutions as

x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k

3 0

2 years ago

What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove

wolverine [178]

Answer:

The solutions are:

$b=0,\:b=4$

Step-by-step explanation:

Considering the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

Solving the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

$\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2$

$5b^3-10=6b^3-4b^2-10$

$\mathrm{Switch\:sides}$

$6b^3-4b^2-10=5b^3-10$

$6b^3-4b^2-10+10=5b^3-10+10$

$6b^3-4b^2=5b^3$

$\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}$

$6b^3-4b^2-5b^3=5b^3-5b^3$

$b^3-4b^2=0$

$Using\:the\:Zero\:Factor\:Principle:$ $if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

So,

$b=0,b-4=0$

$b=0,b=4$

Therefore, the solutions are:

$b=0,\:b=4$

4 0

3 years ago

Read 2 more answers

Which models show 40%? Check all that apply. A model with 4 shaded sections and 6 unshaded sections. A model with 40 shaded sect

Amanda [17]

Answer:

A model with 4 shaded sections and 6 unshaded sections.

A model with 40 shaded sections and 60 unshaded sections.

Step-by-step explanation:

Required:

Which models shows 40%

(a) 4 shaded and 6 unshaded

First, we calculate the total sections

$Total = 4 + 6$

$Total = 10$

The percentage of the shaded section is:

$Shaded = \frac{4}{10} * 100\%$

$Shaded = 0.4 * 100\%$

$Shaded = 40\%$

(b) 40 shaded and 60 unshaded

First, we calculate the total sections

$Total = 40 + 60$

$Total = 100$

The percentage of the shaded section is:

$Shaded = \frac{40}{100} * 100\%$

$Shaded = 0.4 * 100\%$

$Shaded = 40\%$

(c) 2 shaded and 8 unshaded

First, we calculate the total sections

$Total = 2 + 8$

$Total = 10$

The percentage of the shaded section is:

$Shaded = \frac{2}{10} * 100\%$

$Shaded = 0.2 * 100\%$

$Shaded = 20\%$

<em>Hence, (a) and (b) shows 40%</em>

8 0

2 years ago

Read 2 more answers

Properties of exponents<br> Rewrite the expression in the form b^n—— (b^2)^3/7

exis [7]

Answer:

$b^{\frac{6}{7}}$ is the required expression.

Step-by-step explanation:

$(b^2)^{\frac{3}{7}}\\\\\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0\\\\=b^{2\cdot \frac{3}{7}}\\\\=b^{\frac{6}{7}}$

Best Regards!

3 0

3 years ago

A tomato plant grew an average of 0.06 m per day. how many days did it take for the plant to grow a total of 0.96 m?

gizmo_the_mogwai [7]

1 day = 0.06 m
x = 0.96 m

0.96 ÷ 0.06 = 16 days

3 0

2 years ago