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Brilliant_brown [7]

2 years ago

14

Justin used a container shaped like a cylinder for his dog's food. The dimensions of the container are shown below. What is the

measurement closest
to the volume of the container in cubic inches?

1 answer:

sattari [20]2 years ago

5 0

17. ss s s s s s s. ss. s s s s s. s s s s s s f f f f d d d. d

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Vesnalui [34]

Answer : YOU HAVE TO SHOW THE WHOLE PIC PLS SO I CAN HELP U

Step-by-step explanation:

7 0

2 years ago

Math question : Please help

MA_775_DIABLO [31]

The answer to the question is C

5 0

3 years ago

What do we do to both sides of the equation? X-8=3

Alik [6]

Answer:

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We'll add 8 to the both side of the equation on order to get the Value of x
x -8+8 = 3+8
x = 11

~ʆᵒŕ∂ཇꜱꜹⱽẻⱮë

5 0

2 years ago

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Can I get help with finding the Fourier cosine series of F(x) = x - x^2

trapecia [35]

Assuming you want the cosine series expansion over an arbitrary symmetric interval $[-L,L]$ , $L\neq0$ , the cosine series is given by

$f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx$

You have

$a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx$
$a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}$
$a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)$
$a_0=-\dfrac{2L^2}3$

$a_n=\displaystyle\frac1L\int_{-L}^Lf(x)\cos nx\,\mathrm dx$

Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

$\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}$

and so

$a_n=-\dfrac{4L\cos nL}{n^2}+\dfrac{(4-2n^2L^2)\sin nL}{n^3}$

So the cosine series for $f(x)$ periodic over an interval $[-L,L]$ is

$f_C(x)=-\dfrac{L^2}3+\displaystyle\sum_{n\ge1}\left(-\dfrac{4L\cos nL}{n^2L}+\dfrac{(4-2n^2L^2)\sin nL}{n^3L}\right)\cos nx$

4 0

3 years ago

The table shows the battery lives in hours of ten Brand A batteries and ten Brand B batteries.

defon

Plotting the data (attached photo) roughly shows that the data is skewed to the left. In other words, data is skewed negatively and that the long tail will be on the negative side of the peak.

In such a scenario, interquartile range is normally the best measure to compare variations of data.

Therefore, the last option is the best for the data provided.

5 0

3 years ago

Read 2 more answers