All categories

3 years ago

Which function below is growing the fastest?

Mathematics

2 answers:

Assoli18 [71]3 years ago

4 0

Answer:

Function #1

Step-by-step explanation:

cricket20 [7]3 years ago

4 0

Answer:

Step-by-step explanation:

Function #1 is growing faster.

On function #2 y=2 when x=1 or (1,2), and on function #1 y=5 when x=1 or (1,5). Therefor Function #1 is growing at a faster rate.

You might be interested in

9. Write the slope-intercept form of the equation of the line through the given points. Write answer as y=mx+b. through: (-4, 5)

densk [106]

Answer:

y = -x + 1

Step-by-step explanation:

(-4,5) (1,0)

Find distance through a number line.

Distance(Slope):

(5,-5)

Slope form:

y/x, Apply:

-5/5

Reduce:

-1/1 or -1

To find the y-intercept get x to be at zero and see where y ends. Let's use the point (1,0):

(1,0) use slope -1x to get x to zero:

= (0,1)

y-intercept: (0,1)

Now write in slope-intercept form:

y = mx + b

so,

y = -1x + 1 or y = -x + 1 or y = -1/1x + 1

3 0

3 years ago

Read 2 more answers

sarah worked out for 15 today. she plans to add 5 min per week. write qnd equation to represent how many minutes she will be wor

garik1379 [7]

Answer:

I think its 15 + 5x

Step-by-step explanation:

4 0

2 years ago

What are the vertical angles

wariber [46]

It’s the bottom left answer because the angles are opposite of each other. They are also congruent. I hope this helps!

8 0

3 years ago

Read 2 more answers

Consider the following vector-valued function:~h(t) =〈2 sin(3t),3 cos(3t),√5 sin(3t)〉0≤t≤2π3This defines a smooth parameterized

omeli [17]

Answer:

a) h'(t)= (6cos3t,-9sin3t,3 $\sqrt[]{5}$ cos3t)

b) t=0.93994736+πn/3

c) Magnitude of h(t) is 3 which is a constant, so h(t) lies on a sphere

Step-by-step explanation:

5 0

3 years ago

Get the general term for the sequence being your t3 = 11 and the t20 = 244.2

marusya05 [52]

Answer:

nth term = $t_{n} = 7.639(1.2)^{n - 1}$

Step-by-step explanation:

Let us assume that the given sequence is a G.P.

Now, if the first term of the G.P. is a and the common ratio is r, then

Third term = $t_{3} = ar^{2} = 11$ .......... (1) and

20th term = $t_{20} = ar^{19} = 244.2$ ........... (2)

Now, dividing equation (2) with equation (1) we get

$\frac{ar^{19} }{ar^{2} } = \frac{244.2}{11} = 22.2$

⇒ $r^{17} = 22.2$

⇒ r = 1.2.

Hence, from equation (1) we get

a(1.2)² = 11

⇒ a = 7.639 (Approx.)

Therefore, the general term of the sequence i.e. nth term = $t_{n} = 7.639(1.2)^{n - 1}$ (Answer)

5 0

3 years ago