All categories

3 years ago

Which function below is growing the fastest?

Mathematics

2 answers:

Assoli18 [71]3 years ago

4 0

Answer:

Function #1

Step-by-step explanation:

cricket20 [7]3 years ago

4 0

Answer:

Step-by-step explanation:

Function #1 is growing faster.

On function #2 y=2 when x=1 or (1,2), and on function #1 y=5 when x=1 or (1,5). Therefor Function #1 is growing at a faster rate.

You might be interested in

Angle A and angle B are supplementary. The measure of angle B is 82.5.

stealth61 [152]

Answer:

Angle A = 97.5º

Step-by-step explanation:

Supplmentary means 2 angles that equal 180º. So we already have 1 angle, so now all we have to do is subtract 82.5 from 180.

180 - 82.5 = 97.5

5 0

3 years ago

Read 2 more answers

Two machines are used for filling glass bottles with a soft-drink beverage. The filling process have known standard deviations s

stellarik [79]

Answer:

a. We reject the null hypothesis at the significance level of 0.05

b. The p-value is zero for practical applications

c. (-0.0225, -0.0375)

Step-by-step explanation:

Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.

Then we have $n_{1} = 25$ , $\bar{x}_{1} = 2.04$ , $\sigma_{1} = 0.010$ and $n_{2} = 20$ , $\bar{x}_{2} = 2.07$ , $\sigma_{2} = 0.015$ . The pooled estimate is given by

$\sigma_{p}^{2} = \frac{(n_{1}-1)\sigma_{1}^{2}+(n_{2}-1)\sigma_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(25-1)(0.010)^{2}+(20-1)(0.015)^{2}}{25+20-2} = 0.0001552$

a. We want to test $H_{0}: \mu_{1}-\mu_{2} = 0$ vs $H_{1}: \mu_{1}-\mu_{2} \neq 0$ (two-tailed alternative).

The test statistic is $T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}}$ and the observed value is $t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257$ . T has a Student's t distribution with 20 + 25 - 2 = 43 df.

The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value $t_{0}$ falls inside RR, we reject the null hypothesis at the significance level of 0.05

b. The p-value for this test is given by $2P(T$ 0 (4.359564e-10) because we have a two-tailed alternative. Here T has a t distribution with 43 df.

c. The 95% confidence interval for the true mean difference is given by (if the samples are independent)

$(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.05/2}s_{p}\sqrt{\frac{1}{25}+\frac{1}{20}}$ , i.e.,

$-0.03\pm t_{0.025}0.012459\sqrt{\frac{1}{25}+\frac{1}{20}}$

where $t_{0.025}$ is the 2.5th quantile of the t distribution with (25+20-2) = 43 degrees of freedom. So

$-0.03\pm(2.0167)(0.012459)(0.3)$ , i.e.,

(-0.0225, -0.0375)

8 0

3 years ago

I need someone to explain on how to do this problem.

weqwewe [10]

Answer:

I think it's x=-12 for the buttom one

Step-by-step explanation:

I think when you get open equations like these you would asume 1 is there so rewrite it as 2x + 25 = 1

so take the 25 away from 1. to do that we need to do the opisite of +

2x + 25 = 1

1 - 25 = -24

rewrite

2x = -24

take the 2 away. oppisite of mulitplication is division. so divide 2 by -24

-24 divided by 2 = -12

Hope this helps! Please mark as brainliest! Thanks! If you need me to solve the top one too, I'll do it! Just comment bellow. :D

5 0

3 years ago

Read 2 more answers

What is an equivalent mixed number for the decimal 16.3

ZanzabumX [31]

Answer:

The answer is 5 1/3 or five one thirds

3 0

4 years ago

How old is molly if she was 52 years old when she was fourteen years ago?

meriva

To solve a problem like this, we can setup a basic algebraic equation.

52+14=x
66=x

We know this equation is true because 14 years ago, she was 52 so 14 years later, she is 66.

8 0

3 years ago