Answer:
B. The interquartile range is 55
Step-by-step explanation:
the interquartile range is Q3 minus Q1, you would get 15 ,not 55. So B is the answer to your question
L = 8w-32
w(8w-32) = 96
8x^2 - 32w - 96 = 0
w^2 - 4w - 12 = 0
(w - 6)(w + 2 ) = 0
w+2=0 results in negative measures
w-6=0 ---> w = 6
width is 6
length is 8(6) - 32 = 48-32 = 16
Your answer is 15
Good Luck
All you need to do is to break the value into prime factors! Here is how you should work out such problem...
840
= 4 * 210
= 2² * 21 * 10
= 2² * 7 * 3 * 5 * 2
= 2³ * 3 * 5 * 7
Answer:
A) 
Step-by-step explanation:
![f(n) = \sqrt[3]{n} -2](https://tex.z-dn.net/?f=f%28n%29%20%3D%20%5Csqrt%5B3%5D%7Bn%7D%20-2)
![y = \sqrt[3]{n} -2](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%5B3%5D%7Bn%7D%20-2)





Hope this helps!