L = 8w-32
w(8w-32) = 96
8x^2 - 32w - 96 = 0
w^2 - 4w - 12 = 0
(w - 6)(w + 2 ) = 0
w+2=0 results in negative measures
w-6=0 ---> w = 6
width is 6
length is 8(6) - 32 = 48-32 = 16
Answer:
15 cm
Step-by-step explanation:
Given that :
Reading at one end, initial reading = 3.5 cm
Reading at the other end, final reading = 18.5 cm
Length of needle :
Final Reading - Initial reading
18.5cm - 3.5cm
= 15cm
B
Answer: E,C and D