A rectangle has a length of 32feet less than 8 times its width. If the area of the rectangle is 96 square feet, find the length
of the rectangle.
1 answer:
L = 8w-32
w(8w-32) = 96
8x^2 - 32w - 96 = 0
w^2 - 4w - 12 = 0
(w - 6)(w + 2 ) = 0
w+2=0 results in negative measures
w-6=0 ---> w = 6
width is 6
length is 8(6) - 32 = 48-32 = 16
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