A rectangle has a length of 32feet less than 8 times its width. If the area of the rectangle is 96 square feet, find the length
of the rectangle.
1 answer:
L = 8w-32
w(8w-32) = 96
8x^2 - 32w - 96 = 0
w^2 - 4w - 12 = 0
(w - 6)(w + 2 ) = 0
w+2=0 results in negative measures
w-6=0 ---> w = 6
width is 6
length is 8(6) - 32 = 48-32 = 16
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Answer:
Hi there!
Your answer is;
the equation
(w+6)+(w+6)+(w)+(w) = 52
The width of this rectangle is 10. The length of this rectangle is 16.
Step-by-step explanation:
Rectangular perimeter:
l+l+w+w
l= w+6
w= w
(w+6)+(w+6)+(w)+(w)
4w+12= 52
4w = 40
/4
w= 10
Hope this helps!
5/6 - 1/3 × 7/8
5/6 - 7/24
20/24 - 7/24
13/24
do the multiplication first
Answer:
Step-by-step explanation:
That would be 8 x 3. It would help because 24/8 = 3.
1/20x52/1=52/20 which equals to your answer that is 2 3/5
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it depend on the question but if it is asking if they have the same answer then it is true
Step-by-step explanation:
