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faust18 [17]
3 years ago
5

A $4,000.00 principal earns 5% interest, compounded annually. After 4 years, what is the balance in the account?

Mathematics
1 answer:
denis23 [38]3 years ago
6 0
First question:
interest rate is 5% annually. After 4 years relative value of interest will be 1.05^4
Now we multiply that with starting funds and get
4000* 1.05^4 = 4862.03

Second question:
Because interest is 8% semiannually that means that after 35 years relative value of interest will be   1.04^(35*2)
6000*1.04^70 = 93,429.71

Third question:
after first year tractor's value will be 0.86*15450. After 3 years its value will be:
(0.86)^3*15,450 = 9,827.07
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Answer:

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\sf \ln (20)=2.9957

Step-by-step explanation:

<u>Question 1</u>

Given:

  \sf \log_b(3)=1.099

  \sf \log_b(5)=1.609

To evaluate \sf \log_b(75),  replace 75 with (5 × 5 × 3):

\implies \sf \log_b(5 \cdot 5 \cdot 3)

\textsf{Apply the Product log law}: \quad \log_axy=\log_ax + \log_ay

\implies \sf \log_b5+\log_b5+\log_b3

Substitute the given values to solve:

\implies \sf 1.609 + 1.609 + 1.099=4.317

<u>Question 2</u>

Given:

  \sf \ln(4)=1.3863

  \sf \ln(5)=1.6094

To evaluate ln(20) replace 20 with (4 × 5):

\implies \sf \ln (4 \cdot  5)

\textsf{Apply the Product log law}: \quad \ln xy=\ln x + \ln y

<em />\implies \sf \ln (4)+\ln (5)

Substitute the given values to solve:

\implies \sf 1.3863+1.6094=2.9957

5 0
2 years ago
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Step-by-step explanation:

<em>v = πr^2h</em>

v = π7.4^2(11.4)

= π54.76(11.4)

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2 years ago
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Step-by-step explanation:

Step 1: Subtract 6x from both sides

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Step 2: Subtract 16 from both sides

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Step 3: Divide both sides by 4

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And we have our answer!

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