The period of the function is that distance where the function becomes equal again.
We have then:
Part 1:
The period of the function is:
T = 3
Part 2:
The period of the function is:
T = 4
Answer:
The period of functions 1 and 2 respectively are:
T = 3
T = 4
Answer:
fog = 2√(x-1) + 1
Domain = [1, 
)
Step-by-step explanation:
Given the functions f(x)=2x+1 and g(x)=sqrt(x-1), we are to find the composite function fog
fog = f(g(x))
f(g(x)) = f(√(x-1))
f(√(x+1)) means that we are to replace variable x in f(x) with the function √(x-1)
f(√(x-1)) = 2(√(x-1))+1
f(√(x+1)) = 2√(x-1) + 1
fog = 2√(x-1) + 1
<em>For the function to exist on any real valued function, then the function inside square root i.e x-1 must be greater than or equal to zero (x-1≥0)</em>
If x-1≥0
x≥0+1
x≥1
This means the range of variable x must be values of x greater than or equal to 1.
Domain = [1, )
Answer:
-67
Step-by-step explanation:
Answer:
Correct option: first one -> y = (1/3)x + (10/3)
Step-by-step explanation:
The linear function that represents a line is:
y = ax + b
Where a is the slope and b is the y-intercept.
First we need to find the slope of the line that goes through (0, -3) and (3, -2).
Using both points, we can find the equation of the line:
x = 0 -> y = -3
-3 = a*0 + b
b = -3
x = 3 -> y = -2
-2 = 3a - 3
3a = 1
a = 1/3
The parallel line needs to have the same slope as the line, so we can model the parallel line with the following equation:
y = (1/3)x + b
The parallel line goes through the point (-4, 2), so we have:
x = -4 -> y = 2
2 = (1/3)*(-4) + b
b = 2 + (4/3)
b = 10/3
So the equation of the parallel line is:
y = (1/3)x + (10/3)
Correct option: first one
Answer:
Here,
150+10=180
162-180=18
Answer is 18°
Step-by-step explanation:
So the round of nearest tenth is 18°
Hope it will help have a great day at school. ^_^
