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mamaluj [8]
4 years ago
7

Suppose a city with population 100,000 has been growing at a rate of 8​% per year. If this rate​ continues, find the population

of this city in 17 years.
Mathematics
1 answer:
Natalija [7]4 years ago
7 0

Answer:

370,002\ people

Step-by-step explanation:

In this problem we have a exponential equation of the form

y=a(b^x)

where

y is the population of the city

x is the number of years

a is the initial value or y-intercept

b is the base

r is the rate of growth

b=(1+r)

we have

a=100,000\ people\\r=8\%=8/100=0.08\\b=1+0.08=1.08

substitute

y=100,000(1.08^x)

For x=17 years

substitute the value of x in the exponential equation and solve for y

y=100,000(1.08^17)

y=370,002\ people

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Solve for X<br><br> B. X<br> X<br> 152
krok68 [10]

Answer:

Step-by-step explanation:

180 - 152 = 28

2x + 28 = 180

2x = 152

x = 76

3 0
3 years ago
Find the volume of a trough 5 meters long whose ends are equilateral triangles, each of whose
yawa3891 [41]

Answer:

V=5\sqrt{3}\ m^3

Step-by-step explanation:

we know that

The volume of a trough is equal to

V=BL

where

B is the area of equilateral triangle

L is the length of a trough

step 1

Find the area of  equilateral triangle B

The area of a equilateral triangle applying the law of sines is equal to

B=\frac{1}{2} b^{2} sin(60\°)

where

b=2\ m

sin(60\°)=\frac{\sqrt{3}}{2}

substitute

B=\frac{1}{2}(2)^{2} (\frac{\sqrt{3}}{2})

B=\sqrt{3}\ m^{2}

step 2

Find the volume of a trough

V=BL

we have

B=\sqrt{3}\ m^{2}

L=5\ m

substitute

V=(\sqrt{3})(5)

V=5\sqrt{3}\ m^3

3 0
4 years ago
Explain step by step please thank you!
ddd [48]

Answer:

Number of students in district = 3,055 students

Step-by-step explanation:

Given:

Ratio [Teachers to students] = 2 : 47

Total number of teachers in district = 130

Find:

Number of students in district

Computation:

Number of students in district = Total number of teachers in district[47/2]

Number of students in district = 130[47/2]

Number of students in district = 65[47]

Number of students in district = 3,055 students

5 0
3 years ago
Find e-0.3<br><br> A) -0.74<br> B) 0.74<br> C) -1.35
deff fn [24]
E^-0.3 = 0.74 from the calculator
4 0
3 years ago
In December, the average total rainfall in all the deserts together is 0.89 mm. Explain how to use the fiqures from the table to
maw [93]
I know this is late but I can still help answer this....

So we know that in December all the deserts altogether had 0.89 mm of rainfall. Now the chart that you have seems to represent the rainfall in August, so we would need to use addition.
0.19 + 0.17 + 0.1 + 0.24 = 0.70 mm
The rainfall altogether would be 0.70 mm in August. Now we compare the difference, we would need to subtract 0.89 mm (December) with 0.70 mm (August).
0.89 - 0.70 = 0.19 mm
There the difference between the two would be 0.19 mm.

Hope this helps!
6 0
3 years ago
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