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Stells [14]
3 years ago
7

The image of the point (-1,-8) under a translation is (0, -11). Find the coordinates of the image of the point (-4,-1) under the

same translation.​
Mathematics
1 answer:
Vanyuwa [196]3 years ago
4 0

Answer:

(-3,-4)

Step-by-step explanation:

● (-1,-8) => (0,-11)

Notice that to move from -1 to 0 in the x-axis we should go one unit to the right wich means adding 1.

● -1 + 1 = 0

Notice that to move from -8 to -11 in the y-axis we should go 3 units down wich means substracting 3.

● -8-3 = -11

Let's do the same for the second point.

● (-4,-1) => ?

Add 1 to -4

● -4+1 = -3

We moved 1 unit to the right by adding 1

Substract 3 from -1

● -1-3 = -4

We moved down 3 units by substracting 3

So the image of (-4,-1) is (-3,-4)

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Answer:

RADIUS

==================================

PROBLEM

Mary’s bicycle wheel has a circumference of 226.08 cm². What is its radius?

SOLUTION

We can solve this problem using the circumference formula in which π stands for ( 3.14 ), C stands for circumference itself and r stands for radius.

\bold{Formula \: || \: C = 2πr}Formula∣∣C=2πr

\tt{226.08 = 2(3.14) r}226.08=2(3.14)r

'Now to find the radius,Substitute 226.08 for c which is circumference in the formula.

\begin{gathered} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt{C = 2πr} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt{226.08 = 2(3.14)\red{r}} \\ \\ \: \: \: \: \: \: \: \: \large \tt{ \frac{226.08}{6.28} = \cancel\frac{6.28 \red{r}}{6.28} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{\tt\green{C = 36}}\end{gathered}

C=2πr

226.08=2(3.14)r

6.28

226.08

=

6.28

6.28r

C=36

To check:

\begin{gathered} \small\begin{array}{|c|}\hline \bold{circumference }\\ \\ \tt{C = 2πr} \\ \tt{C = 2(3.14) (36\:cm) } \\ \tt{C = 2(113.04\:cm) } \\ \underline{\tt \green{C = 226.08\:cm }} \\ \hline \end{array} \end{gathered}

circumference

C=2πr

C=2(3.14)(36cm)

C=2(113.04cm)

C=226.08cm

FINAL ANSWER

If Mary's Bicycle has a circumference of 226.08 cm then the radius is 36.

\boxed{ \tt \red{r = 36}}

r=36

==================================

#CarryOnLearning

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