Question

NEED HELP ASAP PLEASE What is the area of a rectangle with a length of 3xy and a width of 14x^2y

Answer 1

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{42 {x}^{3} {y}^{2} }}}}}$

Step-by-step explanation:

$\star{ \text{ \: Length \: of \: a \: rectangle \: ( \: l \: ) \: = \: 3xy}}$

$\star{ \sf{ \: Width \: of \: a \: rectangle \: ( \: w \: ) = 14 {x}^{2}y}}$

$\underline{ \sf{Finding \: the \: area \: of \: a \: rectangle \: }}$

$\boxed{ \sf{Area \: of \: a \: rectangle = length \: \: * \: width}}$

$\dashrightarrow{ \sf{Area \: of \: a \: rectangle = 3xy \times 14 {x}^{2} y}}$

$\text{Step \: 1 \: : Multiply \: the \: numbers \: and \: variables \: separately}$

$\dashrightarrow{ \sf{ (3 * 14) \: * \: x \: * \: {x}^{2} \: * \: y \: * \: y}}$

$\dashrightarrow{ \sf{42 * \: x \: * \: {x}^{2} \: * \: y \: * \: y}}$

$\text{step \: 2 \: : Add \: the \: power \: of \: the \: variables \: with \: same \: base.}$

$\dashrightarrow{ \sf{42* {x}^{1 + 2} \: * \: {y}^{1 + 1} }}$

$\dashrightarrow{ \sf{42 {x}^{3} {y}^{2} }}$

The area of a rectangle = 42 x³ y²

$\text{Hope \: I \: helped!}$

$\text{Best \: wishes!}$

~$\text{TheAnimeGirl}$