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den301095 [7]
2 years ago
5

NEED HELP ASAP PLEASE What is the area of a rectangle with a length of 3xy and a width of 14x^2y

Mathematics
1 answer:
LiRa [457]2 years ago
6 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{42 {x}^{3}  {y}^{2} }}}}}

Step-by-step explanation:

\star{ \text{ \: Length \: of \: a \: rectangle \: ( \: l \: ) \:  =  \: 3xy}}

\star{ \sf{   \: Width \: of \: a \: rectangle \: ( \: w \: )  = 14 {x}^{2}y}}

\underline{ \sf{Finding \: the \: area \: of \: a \: rectangle \: }}

\boxed{ \sf{Area \: of \: a \: rectangle = length \: \: * \: width}}

\dashrightarrow{ \sf{Area \: of \: a \: rectangle = 3xy \times 14 {x}^{2} y}}

\text{Step \: 1 \: : Multiply \: the \: numbers \: and \: variables \: separately}

\dashrightarrow{ \sf{ (3 * 14)  \: * \: x \: * \:  {x}^{2}  \: * \: y \: * \: y}}

\dashrightarrow{ \sf{42 * \: x \: * \:  {x}^{2}  \: * \: y \: * \: y}}

\text{step \: 2 \:  : Add \: the \: power \: of \: the \: variables \: with \: same \: base.}

\dashrightarrow{ \sf{42* {x}^{1 + 2} \:  * \:  {y}^{1 + 1} }}

\dashrightarrow{ \sf{42 {x}^{3}  {y}^{2} }}

The area of a rectangle = 42 x³ y²

\text{Hope \: I \: helped!}

\text{Best \: wishes!}

~\text{TheAnimeGirl}

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