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12345 [234]
3 years ago
9

What is the length (in cm) of a rectangle with width 14 cm and area 168² cm​

Mathematics
1 answer:
kati45 [8]3 years ago
4 0

Answer:

12

Step-by-step explanation:

Area = length * width

length = area ÷ width

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I use box method to solve this...: 100x^2+34x+49 I hope you wanted the formula! :)
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The table below gives the cost per person to rent a fishing charter boat. Find the rate of change given that it is constant. Als
Scrat [10]
Basing on the table, in each row, if you divide the cost by the number of people, all of them will yield 55. This means that each person, whether as an individual or in a group, must pay $55 in order to rent a fishing charter boat. 

The answer is letter D.
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4 years ago
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A.

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4 0
3 years ago
The blood cholesterol levels of men aged 55 to 64 are approximately normally distributed with mean 222 mg/dl and standard deviat
tatiyna

Answer:

It is provided that 10% of the men aged 55 to 64 have cholesterol level <u>270 mg/dl</u> or higher.

Step-by-step explanation:

Let <em>X</em> = blood cholesterol levels of men aged 55 to 64 years.

The random variable <em>X</em> follows a Normal distribution with mean <em>μ</em> = 222 mg/dl and standard deviation <em>σ</em> = 37 mg/dl.

It is provided that 10% of the men aged 55 to 64 have cholesterol level <em>x</em> mg/dl or higher.

Compute the value of <em>x</em> as follows:

P(X\geq x)=0.10\\P(\frac{X-\mu}{\sigma}\geq \frac{x-222}{37})=0.10\\P(Z\geq z)=0.10\\1-P(Z

Use the <em>z</em>-table to compute the value <em>z</em> for the probability 0.90.

The value of <em>z</em> is 1.29.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\1.29=\frac{x-222}{37} \\x=222+(1.29\times37)\\=269.73\approx270

Thus, 10% of the men aged 55 to 64 have cholesterol level 270 mg/dl or higher.

3 0
3 years ago
Find the area of the trapezoid.<br> bı = 12. b2 = 6, h = 3<br> The area is<br> square units.
dusya [7]

Answer:27

Step-by-step explanation:

A=((b1+b2)/2)h

A=((12+6)/2)(3)

A=((18)/2)3

A=27

8 0
3 years ago
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