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3 years ago

If trinalge abc= def by side-side-side triangle congruence theorem, then b=e by

2 answers:

8 0

I think the correct answer from the choices listed above is option C. If triangle abc= def by side-side-side triangle congruence theorem, then b=e by Corresponding parts of congruence. CPCTC states that if two or more triangles arecongruent<span>, then all of their </span>corresponding<span> angles and </span>sides<span> are </span>congruent<span> as well.</span>

Anna007 [38]3 years ago

6 0

Answer: D: Corresponding parts of congruent triangles are congruent

Step-by-step explanation:

If two triangle are congruent using postulate of theorems of congruence then their corresponding parts are congruent by CPCTC rule.

The CPCTC rule says that if two triangles are congruent then their each corresponding part whether angles or sides must be equal.

Here if triangle abc= def by side-side-side triangle congruence theorem,

then b=e [which is a corresponding part of both triangles] by Corresponding parts of congruent triangles are congruent.

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Which equation demonstrates the distributive property? A) 2 (5 + 7) = 2 (7 + 5) Eliminate B) 2 (5 + 7) = 2 × 5 + 2 × 7 C) (2 × 5

Gemiola [76]

B) 2 (5 + 7) = 2 × 5 + 2 × 7

Distributing the two multiples the five and seven and adds there them together.

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3 years ago

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Compare and contrast the relative frequency for the whole table in part B with the two-way frequency table given in the activity

PIT_PIT [208]

The way to convert counts into relative frequencies in a Two Way Relative Frequency Table is to divide the count by the total number of items

<h3>What is a Frequency Table?</h3>

This refers to the depiction of the number of times in which an event occurs in the form of a table.

Hence, when a two-way frequency table is used, it shows the visual representation of the possible relationship between different sets of data.

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2 years ago

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vlabodo [156]

Step-by-step explanation:

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2 years ago

Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 sam

Vlad [161]

Answer

$P(A) = 0.30$

$P(B) = 0.77$

$P(A\ n\ B) = 0.22$

$P(A\ u\ B) = 0.85$

Explanation:

Given

See attachment for proper data presentation

$n = 100$ --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

Here:

$Yes = 22$ and $No = 8$

$n(A) = Yes + No$

$n(A) = 22 + 8$

$n(A) = 30$

P(A) is then calculated as:

$P(A) = \frac{n(A)}{Sample}$

$P(A) = \frac{30}{100}$

$P(A) = 0.30$

Solving (b): P(B)

We only consider data in the Yes column.

Here:

$(1) = 22$ $(2) = 25$ and $(3) = 30$

$n(B) = (1) + (2) + (3)$

$n(B) = 22 + 25 + 30$

$n(B) = 77$

P(B) is then calculated as:

$P(B) = \frac{n(B)}{Sample}$

$P(B) = \frac{77}{100}$

$P(B) = 0.77$

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

i.e. [Supplier 1][Yes]

This is represented as: n(A n B)

$n(A\ n\ B) = 22$

The probability is then calculated as:

$P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}$

$P(A\ n\ B) = \frac{22}{100}$

$P(A\ n\ B) = 0.22$

Solving (d): P(A u B)

This is calculated as:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$

This gives:

$P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}$

Take LCM

$P(A\ u\ B) = \frac{30+77-22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

$P(A\ u\ B) = 0.85$

7 0

3 years ago

What’s the value of x?

tatuchka [14]

We have a pair of vertical angles here. So they would equal each other.
3x+50=6x-10
Subtract 3x to 6x:
50=3x-10
Add 10 to 50:
60=3x
Divide 3 to both sides:
x=30

4 0

3 years ago

Read 2 more answers