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NemiM [27]
3 years ago
6

The figure below is a rectangular prism.

Mathematics
1 answer:
castortr0y [4]3 years ago
6 0
D. AH

Segment AH is parallel to BD and if the lines were drawn out infinitely, the two lines would never meet.
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Professor Green is interested in determining the average SAT score for the entire population of individuals who took the SAT. Sh
Dvinal [7]

Answer:

Descriptive statistics

Explanation:

The population average is a descriptive statistic. It informs about how the population looks like, in this case, the population looks like having a average of 1000.

If, using her class's average where to infer the population average that is inferential statistic. But that is not the case

7 0
3 years ago
High school students across the nation compete in a financial capability challenge each year by taking a National Financial Capa
zalisa [80]

Answer:

The students have to score 0.74 standard deviations above the mean to be publicly recognized.

Step-by-step explanation:

A random variable <em>X</em> is said to have a normal distribution with parameters <em>µ</em>    (mean) and <em>σ</em>² (variance).

If X \sim N (\mu, \sigma^{2}), then z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (<em>Z</em>) = 0 and Var (<em>Z</em>) = 1. That is, Z \sim N (0, 1).

The distribution of these <em>z</em>-scores is known as the standard normal distribution.

The <em>z</em>-score is a standardized form of the raw score, <em>X</em>. It is a numerical measurement of the relationship between a value (<em>X</em>) and the mean (<em>µ</em>) in terms of the standard deviation (<em>σ</em>). A <em>z</em>-score of -1 implies that the data value is 1 standard deviation below the mean. And a <em>z</em>-score of 1 implies that the data value is 1 standard deviation above the mean.

Let <em>X</em>  be defined as the scores of students at the National Financial Capability Challenge Exam.

It is provided that the students who score in the top 23% are recognized publicly for their achievement by the Department of the Treasury.

That is, P (X > x) = 0.23.

⇒ P(\frac{X-\mu}{\sigma}>\frac{x-\mu}{\sigma})=0.23

⇒

   P(Z>z)=0.23\\1-P(Z

The value of <em>z</em> for this probability value is:

<em>z</em> = 0.74.

*Use a <em>z</em>-table.

Thus, the students have to score 0.74 standard deviations above the mean to be publicly recognized.

8 0
3 years ago
Need urgent help on this! my grade is falling :(
ludmilkaskok [199]

Answer:

the answer is b

Step-by-step explanation:

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