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2 years ago

The figure below is a rectangular prism.

Mathematics

1 answer:

castortr0y [4]2 years ago

6 0

D. AH

Segment AH is parallel to BD and if the lines were drawn out infinitely, the two lines would never meet.

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What is -2 x -2 x -2 x -2 = to?

kherson [118]

Answer:

since there are an even number of negatives, just ignore them and multiply normally. 2 x 2=4

4 x 2=8

8 x 2=16

The answer is 16

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3 years ago

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PLS HELP ME ASAP FOR 7 and 8!! (MUST SHOW WORK!!) + GIVING BRAINLIEST AND THANKS

VladimirAG [237]

Question 7:

Diameter = 6.2 cm so Radius = 3.1 cm
A=πr² = 3.14 × 3.1² = 30.1754 cm² = 30.18 cm²

Question 8:

Circumference = 2πr
16π = 2πr
therefore 16 = 2r so r = 8cm

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2 years ago

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BlackZzzverrR [31]

Answer:

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2 years ago

Show two ways to multiply 2/15 x 3/20. Then tell wich way is easier and justify your choice

Radda [10]

The easier way to multiply 2/15 by 3/20 will simply be by multiplying the numerators and denominators.

In order to multiply 2/15 x 3/20, we can simply multiply the numerator and the denominator. This will be

= 2/15 × 3/20

= 6/300

= 1/50

Also, in order to multiply the fractions, we can change them to decimal first. This will be:

= 2/15 × 3/20

= 0.133 × 0.15

= 0.01995

In conclusion, multiplying the numerators and denominators is easier and faster.

Read related link on:

brainly.com/question/25328409

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2 years ago

What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth

EleoNora [17]

Check the picture below.

so... you can pretty much see how long RS and QT are, you can just count the units off the grid.

now, let's find QR's length

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&Q&(~ 8 &,& 8~) 
% (c,d)
&R&(~ 14 &,& 16~)
\end{array}~~ 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
QR=\sqrt{(14-8)^2+(16-8)^2}\implies QR=\sqrt{6^2+8^2}
\\\\\\
QR=\sqrt{36+64}\implies QR=\sqrt{100}\implies QR=10$

and let's also find the length for ST

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&S&(~ 20 &,& 16~) 
% (c,d)
&T&(~ 22 &,& 8~)
\end{array}~ 
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
ST=\sqrt{(22-20)^2+(8-16)^2}\implies ST=\sqrt{2^2+(-8)^2}
\\\\\\
ST=\sqrt{4+64}\implies ST=\sqrt{68}\implies ST=\sqrt{4\cdot 17}
\\\\\\
ST=\sqrt{2^2\cdot 17}\implies ST=2\sqrt{17}$

so, add the lengths of all sides, and that's the perimeter of the trapezoid.

8 0

3 years ago

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