Answer:
D point of conncurrency of the altitudes
the second one i am not sure of but that is the first part to your answer
Step-by-step explanation:
Answer:
A and C are correct.
Step-by-step explanation:
A: 15 + 26 is greater than 41 so it will form a triangle
B: 15 + 36 is not equal to 41 so it will not form a triangle
C: 15 squared + 36 squared = 1,521
41 squared = 1,681
Since a squared + b squared not-equals c squared, it will not be a right
triangle.
D: 15 squared + 36 squared = 297
41 squared = 82
A is correct because any 2 sides of a triangle must be greater than the third.
B is incorrect because it cannot equal the third side, but must be greater than.
C is correct because in a right triangle, the sum of the square of the legs must be equal to the square of the hypoteneuse.
D just does not make sense.
Answer:
D
Step-by-step explanation:
We are given that:

And we want to find the value of tan(2<em>x</em>).
Note that since <em>x</em> is between π/2 and π, it is in QII.
In QII, cosine and tangent are negative and only sine is positive.
We can rewrite our expression as:

Using double angle identities:

Since cosine relates the ratio of the adjacent side to the hypotenuse and we are given that cos(<em>x</em>) = -1/3, this means that our adjacent side is one and our hypotenuse is three (we can ignore the negative). Using this information, find the opposite side:

So, our adjacent side is 1, our opposite side is 2√2, and our hypotenuse is 3.
From the above information, substitute in appropriate values. And since <em>x</em> is in QII, cosine and tangent will be negative while sine will be positive. Hence:
<h2>

</h2>
Simplify:

Evaluate:

The final answer is positive, so we can eliminate A and B.
We can simplify D to:

So, our answer is D.
50; 1 pear for every three green apples. 150 divided by three is 50
Given :
A function, f(x) = -6 + 12
To Find :
The value of f(x) when x= -3, x= 0 and x=1.
Solution :
Given function is f(x) = -6 + 12 .
Simplifying above function, we get :
f(x) = 6
Now, the given function is independent of x.
So, for any value of x the the value of functions remains constant.
Hence, this is the required solution.