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stiv31 [10]
3 years ago
13

Express x²-8x+5 in the form (x-a)²-b where a and b are integers

Mathematics
1 answer:
Elis [28]3 years ago
6 0

x^2-8x+16-11= (x-4)^2-11

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An arithmetic sequence is represented in the following table. Enter the missing term of the sequence.
bija089 [108]

a_1=-9\\\\a_2=a_1-8\to a_2=-9-8=-17\\\\a_3=a_2-8\to a_3=-17-8=-25\\\\a_4=a_3-8\to a_4=-25-8=-33\\\\\text{The general term of an arithmetic sequence:}\\\\a_n=a_1+(n-1)d\\\\a_1-first\ term\\d-common\ difference\\\\\text{We have}\ a_1=-9\ \text{and}\ d=-8.\ \text{Substitute:}\\\\a_n=-9+(n-1)(-8)=-9-8n+8=-8n-1\\\\\text{Put n = 43 and calculate}\ a_{43}\\\\a_{43}=-8(43)-1=-344-1=-345\\\\Answer:\ \boxed{?=-345}

4 0
3 years ago
ANSWER FASTTTT!!!
Veseljchak [2.6K]

Answer:

14

Step-by-step explanation:

6 0
3 years ago
To simplify5(2x-7) use distributive property
sveta [45]

Answer:

10×-35

Step-by-step explanation:

5×2=10

5×7=35

So the answer is 10x-35

8 0
3 years ago
Solve the equation -3+1+10x=x+4 <br> hurry homies
ddd [48]

Answer:

x = 2/3

Step-by-step explanation:

combine -3 and 1.  We get -2 there, and now have:

-2 + 10x = x + 4.

Combining the x terms, we get 9x = 6, so that x = 6/9, or x = 2/3

7 0
3 years ago
Read 2 more answers
Find the values of sin2u, cos2u, and tan2u given the figure.
Vadim26 [7]

Givens

y = 2

x = 1

z(the hypotenuse) = √(2^2 + 1^2)  = √5

Cos(u) = x value / hypotenuse = 1/√5

Sin(u) = y value / hypotenuse = 2/√5

Solve for sin2u

Sin(2u) = 2*sin(u)*cos(u)

Sin(2u) = 2(\dfrac{1}{\dsqrt{5}} * \frac{2}{\dsqrt{5}} = \dfrac{2}{5}) = 4/5

Solve for cos(2u)

cos(2u) = - sqrt(1 - sin^2(2u))

Cos(2u) = - sqrt(1 - (4/5)^2 )

Cos(2u) = -sqrt(1 - 16/25)

cos(2u) = -sqrt(9/25)

cos(2u) = -3/5

Solve for Tan(2u)

tan(2u) = sin(2u) / cos(2u) = 4/5// - 3/5 = - 0.8/0.6 = - 1.3333 = - 4/3

Notes

One: Notice that you would normally rationalize the denominator, but you don't have to in this case.  The formulas are such that they perform the rationalizations themselves.

Two: Notice the sign on the cos(2u). The sin is plus even though the angle (2u) is in the second quadrant. The cos is different. It is about 126 degrees which would make it a negative root (9/25)

Three: If you are uncomfortable with the  tan, you could do fractions.

\text{tan(2u)} = \dfrac{\dfrac{4}{5}}{\dfrac{-3}{5} } =\dfrac{4}{5} *\dfrac{5}{-3} =\dfrac{4}{-3}

7 0
3 years ago
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