All categories

3 years ago

What is the ratio of 5 to 6 can you show work thank you

2 answers:

6 0

I'm not sure I get the question. The ratio of 5 to 6 can be written as
5:6, 5/6, or simply as 5 to 6.

This simply means that for every five of one thing, there are 6 of another.

For example, if I have 10 apples, then I have 12 oranges

spayn [35]3 years ago

5 0

Obiosly 5:6 nothing futher can be done

You might be interested in

Prove that the value of the expression 7^8–7^7 +7^6 is divisible by 43.

murzikaleks [220]

Step-by-step explanation:

1. if to evaluate the given experssion, then

7⁶(7²-7+1)=7⁶*43.

2. if to divide this evaluated expression by 43, then

7⁶*43/43=7⁶.

5 0

3 years ago

Jim sells hot dogs for $2.95 each and steak sandwiches for $9.95 each out of his food cart. During a busy outdoor festival, he s

Afina-wow [57]

Step-by-step explanation:

x + y = 985

2.95x + 9.95y = 7343.75

-2.95x - 2.95y = -2905.75

7y = 4438

y= 634 steak sandwiches

x + 634 = 985

x = 351 hot dogs

7 0

3 years ago

Read 2 more answers

Help?? Due tomorrow!!

krek1111 [17]

Just plot the points. easssyyyyyyo

8 0

3 years ago

What has a greater percent of increase? 5 bonus points on 50 point exam or 5 bonus points on a 100 point exam?

yanalaym [24]

5 bonus on 50 is 5/50 *100%=10%
5 bonus on 100 is 5/100 *100%=5%
Answer: for 50 points.

8 0

3 years ago

Read 2 more answers

Can someone please explain how to do these?

Pani-rosa [81]

Answer:

First question answer: The limit is 69

Second question answer: The limit is 5

Step-by-step explanation:

For the first limit, plug in $x=8$ in the expression $(9x-3)$ , that's the answer for linear equations and limits.

So we have:

$9x-3\\9(8)-3\\72-3\\69$

The answer is 69

For the second limit, if we do same thing as the first, we will get division by 0. Also indeterminate form, 0 divided by 0. Thus we would think that the limit does not exist. But if we do some algebra, we can easily simplify it and thus plug in the value $x=1$ into the simplified expression to get the correct answer. Shown below:

$\frac{x^2+8x-9}{x^2-1}\\\frac{(x+9)(x-1)}{(x-1)(x+1)}\\\frac{x+9}{x+1}$

Now putting 1 in $x$ gives us the limit:

$\frac{x+9}{x+1}\\\frac{1+9}{1+1}=\frac{10}{2}=5$

So the answer is 5

3 0

3 years ago