Answer:
54 ft^2
(54 in green box; 2 in grey box)
Step-by-step explanation:
We have 2 similar triangles, ABC and DEF.
The area of triangle DEF is given as 6 sq ft.
Side BC of triangle ABC measures 12 ft.
The corresponding side to BC in triangle DEF is EF. It measures 4 ft.
That gives us a scale factor from triangle DEF to triangle ABC.
<em>To find the scale factor between two similar polygons, divide the length of a side of the second polygon by the length of the corresponding side of the first polygon.</em>
scale factor = BC/EF = (12 ft)/(4 ft) = 3
The scale factor of side lengths is 3.
The ratio of the areas is the square of the scale factor.
ratio of areas = 3^2 = 9
Now multiply the area of the first triangle (DEF) by the ratio of areas to get the area of the second triangle (ABC).
area of triangle ABC = 9 * (area of triangle DEF)
area of triangle ABC = 9 * (6 sq ft)
area of triangle ABC = 54 sq ft
Answer: 54 ft^2
(54 in green box; 2 in grey box)
Answer: 60
Step-by-step explanation:
Find the total number of students.
In this case, there are 8 total students. Multiply 60 * 8 = 480
Add all the numbers up.
85 + 65 + 36 + 48 + 75 + 39 + 72 = 420
480 - 420 = 60
x = 60
the position of the triangle changes
Answer:
x - 13 = -2. (bonus: x = 11)
Step-by-step explanation:
hope this helps
Adjacent divided by the hypotenuse
