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Alex_Xolod [135]
3 years ago
13

Please help with question 14!! BRAINLIEST to correct answer!

Mathematics
1 answer:
dexar [7]3 years ago
8 0

Answer: true

Step-by-step explanation:

Hope this helps

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Somebody HELP ME PLS IM TRYING TO GET MY GRADES UP FROM AN F! IF ITS CORRECT AND HELPFUL U WILL BE BRAINLIEST
kramer

Answer:

144

Step-by-step explanation:

A=BH

your base is 9 and your height is 16. 16 times 9= 144. Hope this helps :)

5 0
2 years ago
Suppose the time to complete a 200-meter backstroke swim for female competitive swimmers is normally distributed with a mean μ =
Natali [406]
Answer: The proportion that will qualify is 0.0314 or 3.14%.

First, we need to find the z-score of a time of 128 seconds. To do this, we find the difference of the mean and score and divide by the standard deviation.

(128 - 141) / 7 = -1.86

Now, use a standard normal distribution table to determine the percent below a z-score of -1.86. That value is 0.0314 or 3.14%.
6 0
3 years ago
Find the product. y5 · y3
dem82 [27]

Answer:

Step-by-step explanation:

y^5*y^3=y^{5+3}=y^8

5 0
3 years ago
In a metal fabrication​ process, metal rods are produced to a specified target length of 15 feet. Suppose that the lengths are n
Leto [7]

Answer:

95% Confidence interval: (14.4537 ,15.1463)

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 feet

Sample mean, \bar{x} = 14.8 feet

Sample size, n = 16

Alpha, α = 0.05

Sample standard deviation, σ = 0.65 feet

Degree of freedom = n - 1 = 15

95% Confidence interval:

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 15 and}~\alpha_{0.05} = \pm 2.1314  

14.8 \pm 2.1314(\dfrac{0.65}{\sqrt{16}} ) \\\\= 14.8 \pm 0.3463 = (14.4537 ,15.1463)  

is the required confidence interval for the true mean length of rods.

3 0
3 years ago
Read 2 more answers
Kevin ran 5 miles in 42 minutes. How many miles per hour did Kevin run? Round to the nearest tenth.
strojnjashka [21]
Kevin ran 8 miles rounded to the nearest tenth
4 0
3 years ago
Read 2 more answers
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