What question are you asking?
it is the same denominator therefore only the numerators are added and the sign is maintained. The answer is -12/9 but it can be reduced to -4/3.
Answer:
20 gallons were used from the tank with the octane rating of 80.
Step-by-step explanation:
Given : One tank of gasoline has an octane rating of 140 and another tank of gasoline has an octane rating of 80. To obtain a mixture of 60 gallons with an octane rating of 120.
To find : How many gallons should be used from the tank with the octane rating of 80?
Solution : Let x be the volume of gas whose octane rating is 140 and
y be the volume of gas whose octane rating is 80.
Then, we form the equation as:
(1) 

or
.........[3]
(2) 
Now multiply equation (2) by 4
...........[4]
Subtract (4) from (3)



Put x in equation [4] we get,





Therefore, x=40 and y=20
So, 20 gallons were used from the tank with the octane rating of 80.
Answer:
G ≈ 1.46
Step-by-step explanation:
Given
G =
, substitute values
G = 
= 
=
≈ 1.46 ( to 2 dec. places )
Answer:
The classmate's only error is that the slope of the parallel line should be 3 aswell.
Step-by-step explanation:
Parallel lines always have the same slope to each other