All categories

3 years ago

Find the values of x and y for which ABCD must be a parallelogram.?

Mathematics

2 answers:

Semmy [17]3 years ago

7 0

2x - 2 = x + 2
2x - x = 2 + 2 = 4
x = 4

5y - 8 = y + 24
5y - y = 24 + 8
4y = 32
y = 8.

oksian1 [2.3K]3 years ago

7 0

I hope this helps you

You might be interested in

Write the equation of the following graph in intercept form.

Kobotan [32]

Answer:

A) $f(x)=0.2(x+2)(x-5)$

Step-by-step explanation:

The graph has x-intercepts at $x=5$ and $x=-2$ , so our factors for the polynomial will be $x+2$ and $x-5$ . This means we can rule out options B and D.

Our graph also has a y-intercept of $y=-2$ when $x=0$ , so if we let $f(x)=-2$ and $x=0$ , we can find the multiplier:

$f(x)=a(x+2)(x-5)\\-2=a(0+2)(0-5)\\-2=a(2)(-5)\\-2=-10a\\\frac{1}{5}=a\\0.2=a$

Thus, the correct equation is A) $f(x)=0.2(x+2)(x-5)$

8 0

2 years ago

Can you make 2/10 in simplest form

Zinaida [17]

1/5 thats the answer

i hope this help you

8 0

3 years ago

Read 2 more answers

Solve the equation 12+ 0.35×=20.05

lbvjy [14]

12 + 0.35X = 20.05
12 + 0.35X - 12 = 20.05 - 12
0.35X = 8.05
0.35X/0.35 = 8.05/0.35
X = 23
Hope this helps!!

8 0

3 years ago

What’s the answer to this ?

Wittaler [7]

Answer:

Step-by-step explanation:

Area is 96, divide that by 4 triangles = Area is 24 per triangle

Area of a triangle = (0.5)(base)(height)

(0.5)(6)(x)=24

3x=24

x=8

6 0

3 years ago

A television network is deciding whether or not to give its newest television show a spot during prime viewing time at night. If

Alinara [238K]

Answer:

Test statistic z= 1.708

Step-by-step explanation:

given that a television network is deciding whether or not to give its newest television show a spot during prime viewing time at night. If this is to happen, it will have to move one of its most viewed shows to another slot.

Sample size n = 827

Sample proportion p = $\frac{438}{827} \\=0.5297$

$H_0: p =0.5\\H_a: p >0.5$

(right tailed test)

This is because they would be interested if more than half viewers are ready for the change

Test statistic = Z = p difference/std error

p difference = 0.0297

Std error = $\sqrt{\frac{pq}{n} } \\=\sqrt{\frac{0.5*0.5}{827} } \\=0.0174$

Z =1.708

p valu e= 0.9562

Since p >0.05 we fail to reject H0

Test statistic z= 1.708

8 0

3 years ago