All categories

3 years ago

T-4t2+ 2t3 what is the degree of the polynomial

Mathematics

1 answer:

Tema [17]3 years ago

6 0

Answer:

The given polynomial is a third degree polynomial.

Step-by-step explanation:

Given polynomial:

$t-4t^2+2t^3$

To find the degree of the polynomial.

Solution:

The degree of the polynomial is defined by the highest exponent of the variable in the given polynomial. In other words, it is the exponent of the highest degree term.

For a polynomial:

$x^a+x^b+x^c$

where $a>b>c$ , the degree of the polynomial can be given as the a $th$ degree as $a$ is the highest exponent of the variable $x$ .

Thus, for the polynomial:

$t-4t^2+2t^3$

The leading term is $2t^3$ since the term has the highest degree of the variable $t$ and the degree of the polynomial = 3

You might be interested in

Match the circle equations in general form with their corresponding equations in standard form. Not all will be used.

Xelga [282]

The standard form of the equation of a circumference is given by the following expression:

 $(x-h)^{2}+(y-k)^{2}=r^{2} \\ \\ where \ (h, k) \ is \ the \ center \ of \ the \ circumference \ and \ r \ the \ radius$

On the other hand, the general form is given as follows:

 $x^{2}+y^{2}+Dx+Ey+F=0 \\ \\ where: \\ D=-2h, \ E=-2k, \ F=h^{2}+k^{2}-r^{2}$ 

In this way, we can order the mentioned equations as follows:

Equations in Standard Form:

 $\bold{a)} \ (x-6)^{2}+(y-4)^{2}=56 \\ \bold{b)} \ (x-2)^{2} + (y+6)^{2}=60 \\ \bold{c)} \ (x+2)^{2}+(y+3)^{2}=18 \\ \bold{d)} \ (x+1)^{2}+(y-6)^{2}=46$

Equations in General Form:

$\bold{1)} \ x^{2}+y^{2}-4x+12y-20=0 \\ \bold{2)} \ x^{2}+y^{2}+6x-8y-10=0 \\ \bold{3)} \ 3x^{2}+3y^{2}+12x+18y-15=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 3, \ the \ equation \ becomes: \\ x^{2}+y^{2}+4x+6y-5=0 \\ \\ \bold{4)} \ 5x^{2}+5y^{2}-10x+20y-30=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 5, \ the \ equation \ becomes: \\ x^{2}+y^{2}-2x+4y-6=0 \\ \\ \bold{5)} \ 2x^{2}+2y^{2}-24x-16y-8=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 2, \ the \ equation \ becomes: \\ x^{2}+y^{2}-12x-8y-4=0$

$\bold{6)} \ x^{2}+y^{2}+2x-12y$

So let's match each equation:

$\bold{From \ a)} \\ \\ (h,k)=(6,4),\ r=2\sqrt{14} \\ D=-12, \ E=-8 \\ F=-4$

Then, its general form is:

$x^{2}+y^{2}-12x-8y-4=0$

First. a) matches 5) 

$\bold{From \ b)} \\ \\ (h,k)=(2,-6),\ r=2\sqrt{15} \\ D=-4, \ E=12 \\ F=-20$

Then, its general form is:

$x^{2}+y^{2}-4x+12y-20=0$

Second. b) matches 1) 

$\bold{From \ c)} \\ \\ (h,k)=(-2,-3),\ r=3\sqrt{2} \\ D=4, \ E=6 \\ F=-5$

Then, its general form is:

$x^{2}+y^{2}+4x+6y-5=0$

Third. c) matches 3)

$\bold{From \ d)} \\ \\ (h,k)=(-1,6),\ r=\sqrt{46} \\ D=2, \ E=-12, \ F=-9$

Then, its general form is: $x^{2}+y^{2}+2x-12y-9=0$

Fourth. d) matches 6)

6 0

3 years ago

Read 2 more answers

Evaluate the algebraic expression -2.3a + 4.6 for the given value 6 help!??!?!?

Illusion [34]

Answer:

someone please answer

Step-by-step explanation:

I need this too

7 0

3 years ago

Find two consecutive whole numbers that 52 lies between.

tensa zangetsu [6.8K]

Think about which perfect squares lies on the immediate left of 52 and which lies on the immediate right of 52. 49 ---- 52 ------- 64 After that, take the square roots of each of the three numbers.

3 0

3 years ago

Read 2 more answers

The slope of the function ƒ (x) = 8 - 2x is _____. 2 - 2 8 -8

neonofarm [45]

Answer:

-2

Step-by-step explanation:

your equation is

f(x) = -2x+8

-2x

-2 is the slope