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3 years ago

9

the figure below shows two half-circles at the ends of a rectangle with the dimensions shown. which is the closet to the area of

the figure in square inches

1 answer:

Pani-rosa [81]3 years ago

8 0

You get 92.56 <span>You add the area of the rectangle to the area of a circle

</span>

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Ricardo had 2 case of video game with the same number of games in each case .he gives 4 games to his brother.Ricardo has 10 game

Drupady [299]

Answer:

7

Step-by-step explanation:

The total number of video games he had to begin with is 4+10=14.

Divide the total games by 2 (cases) and you get 7 games in each case

6 0

3 years ago

What is the slope indicated in the table below? (x) 10, 20, 30, 40 (y) 20, 17, 14, 11

Airida [17]

Answer: 10/-3

Step-by-step explanation: in the x it’s increasing by 3 and in The y it’s decreasing by 3 so it becomes -3 and you can not symplif 10/-3 so the answer is just 10/-3

6 0

3 years ago

What is the length of segment AB?

AlekseyPX

Answer:

length of segment AB is 13

OR

AB = 13

Step-by-step explanation:

Use the Pythagorean Theorem with c being the length of segment AB.

a^2 + b^2 = c^2

5^2 + 12^2 = c^2

169 = c ^2 (square root both sides to get c by itself)

13 = c

5 0

3 years ago

Translate to an algebraic expression. 26 more than q

Umnica [9.8K]

A= 26 > q

if it says 26 grader than it means the mouth opens to that 26
if it says 26 less then it means the mouth is facing to the q
but it is not so it is the mouth facing the 26

6 0

3 years ago

A company manufactures tires at a cost of $40 each. The following are probabilities of defective tires in a given production run

asambeis [7]

Answer:

The expected cost of the company for a 3000 tires batch is $120255

Step-by-step explanation:

Recall that given a probability of defective tires p, we can model the number of defective tires as a binomial random variable. For 3000 tires, if we have a probability p of having a defective tire, the expected number of defective tires is 3000p.

Let X be the number of defective tires. We can use the total expectation theorem, as follows: if there are $A_1,\dots, A_n$ events that partition the whole sample space, and we have a random variable X over the sample space, then

$E(X) = p(A_1)E(X|A_1) + \dots + p(A_n)E(X|A_n)$ .

So, in this case, we have the following

$E(X) = P(p=0\%)E(X|p=0\%)+P(p=1\%)E(X|p=1\%)+P(p=2\%)E(X|p=2\%)+P(p=3\%)E(X|p=3\%) = 0.1\cdot 3000\cdot 0 + 0.3\cdot 3000\cdot 0.01+ 0.4\cdot 3000\cdot 0.02+ 0.2\cdot 3000\cdot 0.03 = 51$ .

Let Y be the number non defective tires. then X+Y = 3000. So Y = 3000-X. Then E(Y) = 3000-E(X). Then, E(Y) = 2949.

Finally, note that the cost of the batch would be 40Y+45X. Then

$E(40Y+45X) = 40E(Y)+45E(X) = 40\cdot 2949+45\cdot 51=120255$

3 0

3 years ago