Answer:
10 quarters = $2.50
10 nickels = $0.50
that leaves $0.20 for other coins (dimes / pennies)
Step-by-step explanation:
First, suppose she has only quarters and nickels and no other coins. Then if C is the identical number of coins of each type, then 5C + 25C = 320, so 30C = 320 and 3C = 32, but there is no integer solution to this. So she must have at least one other type of coin.
Assume she has only quarters, nickels, and dimes. Then if D is the number of dimes, 5C + 25C + 10D = 320, which means 30C + 10D = 320, or 3C + D = 32. The smallest D can be is 2, leaving 3C = 30 and thus C = 10. So in this scenario she would have 10 quarters, 10 nickels, and two dimes to make $2.50 + $0.50 + $0.20 = $3.20.
This has to be the highest number, because if she had 11 quarters and 11 nickels, that alone would add up to 11(0.25) + 11(0.05) = $3.30, which would already be too much.
Answer:
400cm^2
Step-by-step explanation:
For this question, you need to find the surface areas of both objects, then add them together.
For the cube:
56cm for the front
56cm for the back
42cm for the side
42cm for the other side
48cm for the top
48cm for the bottom
SA for the cube: 292cm^2
For the triangle, things are a little different. We do the same process that we did to find the SA of the cube, but we do not have to find the SA of the top side (because there isn't a top side) and we have to divide the total SA by 2 because it's a triangle.
For the triangle:
42cm for the front
42cm for the back
54cm for the slanted side
42cm for the other side
36cm for the bottom
SA for the triangle: (216/2)^2=108cm^2
292+108=400cm^2
the SA of the composite figure is 400cm^2
Answer:
83%
Step-by-step explanation:
you take 210 - 35 over 210 which is 170 over 210 divide and you get rounded about .83 that as a percent is 83%
To solve this problem,
we must recall that the formula for money with compound interest is calculated
as:
Total = Principal × (
1 + Rate ) ^ n
Total = $2,200 × ( 1 +
0.024 ) ^ 1
Total = $2,252.80
<span>Therefore the answer
is letter B.</span>
