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Veseljchak [2.6K]
4 years ago
14

Plz help me it will be appreciated

Mathematics
1 answer:
Mumz [18]4 years ago
7 0
<h2>Hello!</h2>

The answer is:

A) The solution to the inequality is all the values of "x" less than -3.

<h2>Why?</h2>

To solve the problem, we must remember that isolating variables from inequalities and equalities are almost the same, however, we must remember that the solutions to both have completely different meanings.

Inequalities usually are used to express where a determined function exists, and are referred to restrictions or conditions.

So, we are given the following inequality:

-7x>21

Then, solving we have:

-7x>21

-x>\frac{21}{7}\\\\-x>3\\\\x

Hence, the solution to the inequality are all the values of "x" less than -3.

It can be also written like: (-∞,-3)

So, the correct option is the last graph:

A) The solution to the inequality is all the values of "x" less than -3.

Have a nice day!

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Help please!! I'm having trouble with this question
Fiesta28 [93]

Answer:

the least value would be 85

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
8. Solve the system using elimination.<br> 3x - 4y = 9<br> - 3x + 2y = 9
olga nikolaevna [1]

Answer:

3x−4y=9 −3x+2y=9

Add these equations to eliminate x: −2y=18

Then solve−2y=18

for y: −2y=18 −2y −2 = 18 −2 (Divide both sides by -2)

y=−9

Now that we've found y let's plug it back in to solve for x.

Write down an original equation: 3x−4y=9

Substitute−9for y in 3x−4y=9: 3x−(4)(−9)=9

3x+36=9(Simplify both sides of the equation)

3x+36+−36=9+−36(Add -36 to both sides)

3x=−27 3x 3 = −27 3 (Divide both sides by 3) x=−9

Answer: x=−9 and y=−9

Hope This Helps!!!

4 0
3 years ago
How do I solve this question?
zubka84 [21]

Answer:

f(x) = \frac{108}{7} (\frac{7}{6})^x or f(x) = 15.429(1.167)^x

Step-by-step explanation:

No need for a calculator.

Assuming that the equation is in the form y = ab^x, we can plug in points to get our equation. For ease, let's use (1,18) and (2,21). When plugging these points in, we get 18 = ab^1, 21 = ab^2. Now let's divide the equations to get rid of a: \frac{21 = ab^2}{18 = ab^1}  = \frac{21}{18}  =  \frac{7}{6}  = b. Now that we have b, we can plug in the value we just calculated to solve for a: 18 = a(\frac{7}{6} )^1, and solving for a, we get a = \frac{108}{7}.

So the f(x) = (\frac{108}{7})(\frac{7}{6}  )^x

This equation in decimal form (rounded to the nearest thousandth) is f(x) = 15.429(1.167)^x.

hope this helped! :)

4 0
2 years ago
Using the letters GBLAOKZE you select the A from the group without replacing the A,you select a second letter.find P(not K)
andre [41]

Answer:

Step-by-step explanation:

After selecting A there are 6 letters that are not K out of the remaining 7 letters so

P(!K)=6/7

5 0
3 years ago
Location is known to affect the number, of a particular item, sold by HEB Pantry. Two different locations, A and B, are selected
12345 [234]

Answer:

d) [-16.03,-3.97]

-16.03 \leq \mu_A -\mu_B \leq -3.97.

Step-by-step explanation:

Notation and previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

n_A=18 represent the sample of A

n_B =13 represent the sample of B

\bar x_A =39 represent the mean sample  for A

\bar x_B =49 represent the mean sample for B  

s_A =8 represent the sample deviation for A

s_B =4 represent the sample deviation for B

\alpha=0.01 represent the significance level

Confidence =99% or 0.99

The confidence interval for the difference of means is given by the following formula:  

(\bar X_A -\bar X_B) \pm t_{\alpha/2}\sqrt{(\frac{s^2_A}{n_A}+\frac{s^2_B}{n_B})} (1)  

The point of estimate for \mu_A -\mu_B is just given by:  

\bar X_A -\bar X_B =39-49=-10  

The appropiate degrees of freedom are df=n_1+ n_2 -2=18+13-2=29

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,29)".And we see that t_{\alpha/2}=2.756  

The standard error is given by the following formula:  

SE=\sqrt{(\frac{s^2_A}{n_A}+\frac{s^2_B}{n_B})}  

And replacing we have:  

SE=\sqrt{(\frac{8^2}{18}+\frac{4^2}{13})}=2.188  

Confidence interval  

Now we have everything in order to replace into formula (1):  

-10-2.756\sqrt{(\frac{8^2}{18}+\frac{4^2}{13})}=-16.03  

-10+2.756\sqrt{(\frac{8^2}{18}+\frac{4^2}{13})}=-3.97  

So on this case the 99% confidence interval for the differences of means would be given by -16.03 \leq \mu_A -\mu_B \leq -3.97.

d) [-16.03,-3.97]

7 0
4 years ago
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