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Bad White [126]
3 years ago
5

An automobile producing company operates car dealerships that sell its cars. In order to assess the service costumers get at the

dealerships a team from the Customer Relationship Department was assembled. The team was sent to 20 randomly selected dealerships. Each dealership was visited once by the team for an entire working day. During a visit the team interviewed all the customers that arrived at the that dealership. One of the questions that each of the customers were asked is: "Do you currently possess a car made by our company?
Mathematics
1 answer:
harina [27]3 years ago
4 0

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to assess the service customers receive at the dealerships.

1) The population in this survey is:

The population is the customers of car dealerships.

2) The sample in this survey is:

The random sample taken was 20 selected car dealerships, where the customers were surveyed.

3) A parameter that may be targeted by the survey is:

To study the service the customers receive at the dealerships and if it has any influence in the customers owning or not a car of the company, one parameter to study is the population proportion of customers that own a car of the company vs the proportion of customers that are satisfied with the service received.

4) A statistic that may be used to summarize the outcome of the survey is:

The statistic to use to summarize the outcome of the survey is the sample proportion.

I hope it helps!

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Convert the time. Enter your answer in the box.<br><br> 4 minutes 53 seconds = <br> seconds
ch4aika [34]

Answer:

293 seconds

Step-by-step explanation:

60*4=240

240+53=293

3 0
2 years ago
All vectors are in Rn. Check the true statements below:
Oduvanchick [21]

Answer:

A), B) and D) are true

Step-by-step explanation:

A) We can prove it as follows:

Proy_{cv}y=\frac{(y\cdot cv)}{||cv||^2}cv=\frac{c(y\cdot v)}{c^2||v||^2}cv=\frac{(y\cdot v)}{||v||^2}v=Proy_{v}y

B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that ||Ax||=\sqrt{(A_1 x)^2+\cdots (A_n x)^2}. Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then ||Ax||=\sqrt{(x_1)^2+\cdots (x_n)^2}=||x||.

C) Consider S=\{(0,2),(2,0)\}\subseteq \mathbb{R}^2. This set is orthogonal because (0,2)\cdot(2,0)=0(2)+2(0)=0, but S is not orthonormal because the norm of (0,2) is 2≠1.

D) Let A be an orthogonal matrix in \mathbb{R}^n. Then the columns of A form an orthonormal set. We have that A^{-1}=A^t. To see this, note than the component b_{ij} of the product A^t A is the dot product of the i-th row of A^t and the jth row of A. But the i-th row of A^t is equal to the i-th column of A. If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then A^t A=I    

E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.

In fact, every orthogonal set in R^n without zero vectors is linearly independent. Take a orthogonal set \{u_1,u_2\cdots u_p\} and suppose that there are coefficients a_i such that a_1u_1+a_2u_2\cdots a_nu_n=0. For any i, take the dot product with u_i in both sides of the equation. All product are zero except u_i·u_i=||u_i||. Then a_i||u_i||=0 then a_i=0.  

5 0
3 years ago
I will give brainliest
s344n2d4d5 [400]

Answer: she was not correct, she messed up the equation.

7 0
2 years ago
I NEED HELP FAST ON #6 PLEASE HELP!
Advocard [28]

Answer:

money owed (in order): $850, $870.40, $891.29, $912.68

Step-by-step explanation:

The formula is

money owed = amount owed the previous week + amount owed previous week × interest rate (in decimal form)

so thats:

money owed = amount owed the previous week + amount owed previous week × 0.024

we can simplify that to:

money owed = amount owed the previous week x (1.024)

after 0 weeks:

$850 (just started, no interest added)

after 1 week:

$870.40

after 2 weeks:

$891.29

after 3 weeks:

$912.68

4 0
3 years ago
A standard deck of playing cards has 13 cards in each of four suits: hearts, clubs, diamonds, and spades. Two cards are chosen f
Aloiza [94]

Answer:

Probability of choosing one club and one spade = 0.6025

Step-by-step explanation:

Total number of cards= 52 cards

For the first event

Probability of choosing a club

Toatal club = 13 cards

Probability of choosing a club

= 13/52

Probability of choosing a club

= 1/4

Probability of choosing a club

=0.25

For the second event

Probability of choosing a spade

Toatal spade = 13 cards

Probability of choosing a spade

= 13/52

Probability of choosing spadep

= 1/4

Probability of choosing a spade = 0.25

Probability of both = 0.25*0.25

Probability of both = 0.6025

5 0
2 years ago
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