Answer:
-2 + 11h
Step-by-step explanation:
To simplify this equation, you can first combine like terms:
( -1 + -1 ) + ( -3h + -8h )
-2 + -11h
Count the number of positive integers less than 100 that do not contain any perfect square factors greater than 1.
Possible perfect squares are the squares of integers 2-9.
In fact, only squares of primes need be considered, since for example, 6^2=36 actually contains factors 2^2 and 3^2.
Tabulate the number (in [ ])of integers containing factors of
2^2=4: 4,8,12,16,...96 [24]
3^2=9: 9,18,....99 [11]
5^2=25: 25,50,75 [3]
7^2=49: 49,98 [2]
So the total number of integers from 1 to 99
N=24+11+3+2=40
=>
Number of positive square-free integers below 100 = 99-40 = 59
Answer:
A^k/b^k
Step-by-step explanation:
A/b^k=a^k/b^k
