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3 years ago

I need help with this science problem

Chemistry

1 answer:

Olin [163]3 years ago

5 0

The formula is given, so this is basically a plug and chug problem.

Given values:

$\lambda=530*10^{-9}\text{ m}\\c=3.0*10^8\text{ m/s}$

Plugging these values into the given equation, we get:

$f=\frac{c}{\lambda} =\frac{3.0*10^8\text{ m/s}}{530*10^{-9}\text{ m}} =1.8265*10^{17}{\text{ s}}^{-1}=1.8265*10^{17}\text{ Hz}$

This is a 2 sig fig problem, so your final answer should be $1.8265*10^{17}\text{ Hz}$ .

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Moles of NaOH = Molarity x volume = 10.0 M x 6.7 mL / 10^3 L = 0.067 moles

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Setup the reaction table as follows :

Tris – HCl + OH^- -> Tris + H_2O + Cl^-

0.200 0.067 Initial

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The buffer is diluted to ! L and half the solution is taken. So half the moles of tris – HCl and tris are present.

Moles of Tris – HCl = 0.133 / 2 = 0.0665 moles

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To this solution, 0.0150 mol of H+ are added. H+ reacts with tris giving Tris – HCl. So moles of tris – HCl = 0.0665 + 0.0150 = 0.0815 moles

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When all the 0.018 moles of Tris are consumed, the remaining capacity of the buffer is exhausted.

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