Answer:
= 8350 joules
Solution and explanation:
- The heat of fusion refers to the quantity of heat released when a given amount of water freezes.
- For example, 1 g of water releases 334 J when it freezes at 0°C.
Therefore; For 25.0 g of water.
Heat released = Mass of water × heat of fusion
= 25 g × 334 J/g
= 8350 Joules
Hence, the amount of heat released when 25.0 g of water freezes at 0°C is 8350 J.
Answer:
hmmmm not sure and don't know
Explanation:
Answer: The movement of heat from a warmer object to a cooler one is called heat transfer
Explanation:
Hey there!:
Molar mass CO2 = 44.01 g/mol
44.01 g CO2 ------------------- 6.02*10²² molecules CO2
88 g CO2 ------------------------ y
y = 88 * ( 6.02*10²² ) / 44.01
y = 5.29*10²⁵ / 44.01
y = 1.2 * 10²⁴ molecules of CO2
Answer A
Hope that helps!
Given teh equation adn the heat of reaction, reaction 2's heat of reaction can be obtained by simply multiplying teh heat of reaction of 1 by 3. The final answer is -6129 kJ.
