Hydrogen
If there wasn't any hydrogen at all, we would all be dry like a log in the Sahara Desert. Almost everywhere you can find hydrogen, whether it be little particles in the air, to small particles in the ground.
Answer:
0.58 atm
Explanation:
Step 1: Given data
- Total pressure of the gaseous mixture (P): 1.05 atm
- Partial pressure of N₂ (pN₂): 0.35 atm
- Partial pressure of H₂ (pH₂): 0.12 atm
- Partial pressure of CO₂ (pCO₂): ?
Step 2: Calculate the partial pressure of CO₂
The total pressure of the gaseous mixture is equal to the sum of the partial pressures of the individual gases.
P = pN₂ + pO₂ + pCO₂
pCO₂ = P - pN₂ - pO₂
pCO₂ = 1.05 atm - 0.35 atm - 0.12 atm = 0.58 atm
Unfortunately, your question is incomplete So, according to the attached picture of the complete question we will explain the answer:
according to the reaction equation:
C(s) + 2H2(g) ↔ CH4(g) ΔH° = -74.6KJ
So the true answer will be
D i and ii
- as by adding more C and it is a reactant so the reaction will go rightward to the product to decrease the C to achieve the equilibrium again, the movement of the reaction towards the products will make the CH4 increase
- and by decreasing the Heat and the heat here is as a product as the reaction is exothermic so by decreasing the heat the reaction will go toward the products to increase the heat and achieve the equilibrium again, and that also makes the CH4 increase as it is a product.
So the true answer is
D i and ii as the attached photo
The electron domain geometry is trigonal bipyramidal while the molecular geometry of the compound is seesaw.
The shapes of molecules is determined by the number of electron pairs on the valence shell of the central atom in the molecule. These electron domains include lone pairs and bond pairs.
The lone pairs only contribute towards the electron domain geometry and not the molecular geometry. SCl4 has five electron domains hence its electron domain geometry is trigonal bipyramidal. The molecular geometry of the compound is seesaw.
Learn more: brainly.com/question/6505878