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3 years ago

Reaching a conclusion by looking at several examples is called

1 answer:

7 0

Inductive reasoning

But, inductive reasoning is the process of arriving at a conclusion based on a set of observations. In itself, it is not a valid method of proof eg ...For example, a conclusion that all swans are white is false, but may have been thought true in Europe until the settlement of Australia, when Black Swans were discovered......

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If you were to roll the dice one time, what is the probability it will land on a 2?

vladimir2022 [97]

Answer:

1 out of 6

Step-by-step explanation:

6 0

3 years ago

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One bag contains 3/5 kg of corn. A farmer feeds his chickens 4 bags of corn each week. How many kilograms of corn do they eat ea

saveliy_v [14]

Total kg of corn those chickens eat=3/5 x 4=12/5=2,4
so 1 week=7 days, so corns eat by chickens/day will be 2,4/7

4 0

3 years ago

Solve for points....

Ivan

Answer:

Step-by-step explanation:

For Mr Rowley,

Ratio of Number of home works to the number of exit tickets = $\frac{12}{14}$

= $\frac{6}{7}$

= 6:7

For Ms Rivera,

Ratio of Number of home works to the number of exit tickets = $\frac{36}{42}$

= $\frac{6}{7}$

= 6:7

Since, both the ratios are same, fractions will be proportional.

$\frac{12}{14}=\frac{36}{42}$

7 0

3 years ago

Given that tangent theta = negative 1, what is the value of secant theta, for StartFraction 3 pi Over 2 EndFraction less-than th

vivado [14]

The value of tangent theta is equal to the negative 1. At this value the value of secant theta is $\sqrt{2}$ .

<h3>What is tangent theta?</h3>

The tangent theta in a triangle is the ratio of sine theta and cos theta. It can be written as,

$\rm tan\theta=\dfrac{sin \theta}{cos \theta}$

Given information-

The value of tangent theta is equal to the negative 1.

$\tan \theta=-1$

The tangent theta in a triangle is the ratio of sine theta and cos theta. It can be written as,

$\rm tan\theta=\dfrac{sin \theta}{cos \theta}$

The value of tangent theta is equal to the negative 1. Thus put the value in above expression as,

$\rm -1=\dfrac{sin \theta}{cos \theta}\\$

Simplify it further as,

$\rm -cos \theta=sin \theta$

When the value of cosine and sine theta is equal, then the angle exist in 4th quadrant with the value of $\dfrac{7\pi}{4}$ . Which extent to the $\sqrt{2}/2$ for the cosine function.

In the trigonometry cosine theta is the reciprocal of the secant theta. Thus,

$\rm \dfrac{1}{sec\theta}=\dfrac{\sqrt{2}}{2}\\sec\theta=\sqrt{2}$

Thus the value of secant theta is $\sqrt{2}$

Learn more about the tangent theta here;

brainly.com/question/29190

4 0

3 years ago

Read 2 more answers

Consider the following differential equation. x^2y' + xy = 3 (a) Show that every member of the family of functions y = (3ln(x) +

Veronika [31]

Answer:

Verified

$y(x) = \frac{3Ln(x) + 3}{x}$

$y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{x}$

Step-by-step explanation:

Question:-

- We are given the following non-homogeneous ODE as follows:

$x^2y' +xy = 3$

- A general solution to the above ODE is also given as:

$y = \frac{3Ln(x) + C }{x}$

- We are to prove that every member of the family of curves defined by the above given function ( y ) is indeed a solution to the given ODE.

Solution:-

- To determine the validity of the solution we will first compute the first derivative of the given function ( y ) as follows. Apply the quotient rule.

$y' = \frac{\frac{d}{dx}( 3Ln(x) + C ) . x - ( 3Ln(x) + C ) . \frac{d}{dx} (x) }{x^2} \\\\y' = \frac{\frac{3}{x}.x - ( 3Ln(x) + C ).(1)}{x^2} \\\\y' = - \frac{3Ln(x) + C - 3}{x^2}$

- Now we will plug in the evaluated first derivative ( y' ) and function ( y ) into the given ODE and prove that right hand side is equal to the left hand side of the equality as follows:

$-\frac{3Ln(x) + C - 3}{x^2}.x^2 + \frac{3Ln(x) + C}{x}.x = 3\\\\-3Ln(x) - C + 3 + 3Ln(x) + C= 3\\\\3 = 3$

- The equality holds true for all values of " C "; hence, the function ( y ) is the general solution to the given ODE.

- To determine the complete solution subjected to the initial conditions y (1) = 3. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

$y( 1 ) = \frac{3Ln(1) + C }{1} = 3\\\\0 + C = 3, C = 3$

- Therefore, the complete solution to the given ODE can be expressed as:

$y ( x ) = \frac{3Ln(x) + 3 }{x}$

- To determine the complete solution subjected to the initial conditions y (3) = 1. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

$y(3) = \frac{3Ln(3) + C}{3} = 1\\\\y(3) = 3Ln(3) + C = 3\\\\C = 3 - 3Ln(3)$

- Therefore, the complete solution to the given ODE can be expressed as:

$y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{y}$

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3 years ago