Answer:
t = √1.5/g
Step-by-step explanation:
1/2gt^2 = 3
Divide both sides by 1/2
gt^2 = 1.5
Divide both sides by g
t^2 = 1.5/g
Square root both sides
t = √1.5/g
Answer:
y=5x+31
Step-by-step explanation:
y=mx+b
1=(-6*5)+b
1=-30+b
31=b
y=5x+31
(5*-6)+31
-30+31
1
you can also graph a line on desmos
Answer:
24
Step-by-step explanation:
12 x 2
Answer:
x ≤ 90?
Step-by-step explanation:
For question number 1:The plot H = H(t) is the parabola and it reaches its maximum in the moment when exactly at midpoint between the roots t = 0 and t = 23. At that moment t = 23/2 or 11.5 seconds.
For question number 2:To find the maximal height, just simply substitute t = 11.5 into the quadratic equation. The answer would be 22.9.
For question number 3:H(t) = 0, or, which is the same as -16t^2 + 368t = 0.Factor the left side to get -16*t*(t - 23) = 0.t = 0, relates to the very start of the process, when the ash started its way up.The other root is t = 23 seconds, and it is precisely the time moment when the bit of ash will go back to the ground.
