Number 5 to 10 please

Given: ∆PQR, m∠R = 90° m∠PQR = 75° M ∈ PR , MP = 18 m∠MQR = 60° Find: RQ

tensa zangetsu [6.8K]

Answer: RQ= 8.99 ( approx)

Step-by-step explanation:

Let MR= x

Since, In triangle, PRQ, tan 75°= $\frac{18+x}{RQ}$

⇒ RQ= $\frac{18+x}{tan 75^{\circ}}$

Now, In triangle MRQ,

tan 60°= $\frac{18+x}{RQ}$

⇒ RQ= $\frac{x}{tan 60^{\circ}}$

On equating both values of RQ,

$\frac{18+x}{tan 75^{\circ}}=\frac{x}{tan 60^{\circ}}$

⇒ $\frac{18+x}{x}=\frac{tan 75^{\circ}}{tan 60^{\circ}}$

⇒ $\frac{18+x}{x}=2.15470053838$

⇒ $18=2.15470053838x-x$

⇒ $x=15.5884572681$ ≈15.60

Thus RQ=8.99999999999≈8.99

6 0

3 years ago

Add.

Ann [662]

Answer:

17. +5-2-1=+2

18. -7-6-2=15

19. +11-9-4=-2

20.+4-8+6=+2

6 0

3 years ago

Jason wants to fill a cylindrical water tank to its full capacity. He knows that the volume of the tank is equal to the product

almond37 [142]

Answer:

The answer is B ⇒ $\sqrt{\frac{V}{15\pi }}=10$

Step-by-step explanation:

∵ v = π r² h

∴ r² = $\frac{V}{\pi h }$

∴ r = $\sqrt{\frac{V}{\pi h}}$

∵ r = 10 ft and h = 15 ft

∴ $10=\sqrt{\frac{V}{15\pi } }$

4 0

3 years ago

Read 2 more answers

This graph shows the temperature in Diego's house between noon and midnight one day.

Finger [1]

A. The temperature goes higher-lower-steady/same-lower-same.
B. I do not understand the question

8 0

3 years ago

Evaluate each expression for t = 0, x = 1.5, y = 6, and z = 23

My name is Ann [436]

Answer:

1. 11

2. 20

3. 34

4. 12.6

5. 18

6. 105

Step-by-step explanation:

We are told that ---> t = 0, x = 1.5, y = 6, and z = 23

1. y + 5

= 6 + 5

= 11

2. z - 2x

= 23 - 2(1.5)

= 23 - 3

= 20

3. 2z - 2y

= 2(23) - 2(6)

= 46 - 12

= 34

4. 2.6y - 2x

= 2.6(6) - 2(1.5)

= 15.6 - 3

= 12.6

5. 4(y - x)

= 4(6 - 1.5)

= 24 - 6

= 18

6. 4(2 + z) + 5

= 4(2 + 23) + 5

= 8 + 92 + 5

= 105

3 0

3 years ago