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3 years ago

This graph shows the temperature in Diego's house between noon and midnight one day.

Mathematics

1 answer:

Finger [1]3 years ago

8 0

A. The temperature goes higher-lower-steady/same-lower-same.
B. I do not understand the question

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Devon is paving a rectangular driveway. The driveway is 25.3 meters long and 18.4 meters wide. The formula for the area of a rec

Firdavs [7]

Area of the driveway is 465.52m2

5 0

3 years ago

See attached file. show all work.

andrew11 [14]

The point-slope form of the equation for a line can be written as

... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)

Your function gives

... f'(h) = m

... f(h) = k

a) The tangent line is then

... y = 5(x -2) +3

b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.

... y = (-1/5)(x -2) +3

_____

You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.

In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.

3 0

3 years ago

Is -2018/2017 irrational or rational ?

Mars2501 [29]

-2018/2017 is irrational.

8 0

3 years ago

Read 2 more answers

Richard and Teo have a combined age of 37. Richard is 4 years older than twice Teo's age. How old are Richard and Teo?

valkas [14]

Answer:

Teo is 11 years old and Richard is 26 years old.

Step-by-step explanation:

Let R be the age of Richard and T be the age of Teo.

First set up the equations:

The combined age of Teo and Richard is 37:

R+T=37

Richard is four years old than twice Teo's age:

R=2T+4

Then, solve the equations:

Substitute (2) to (1) and solve for T:

(2T+4)+T=37

3T=11

T=11

Solve for R using (2):

R=2(11)+4

R=22+4

R=26

5 0

3 years ago

How much more would $1,000 earn in 5 years in an account compounded continuously than an account compounded quarterly if the int

s2008m [1.1K]

Answer: There is a difference of $ 1.0228.

Explanation: Given, initial amount or principal = $ 1000,

Time= 5 years and given compound rate of interest = $3.7%

Now, Since the amount in compound continuously,

$A= Pe^{rt}$ , where, r is the rate of compound interest, P is the principal amount and t is the time.

Here, P=$ 1000, t=5 years and r= $3.7%,

Thus, amount in compound continuously , $A=1000e^{3.7\times5/100}$

⇒ $A=1000e^{18.5}=1000\times 1.20321844013=1203.21844013$

Therefore, interest in this compound continuously rate =1203.21844013-1000=203.21844013

now, Since the amount in compound quarterly,

$A=P(1+\frac{r/4}{100} )^{4t}$ , where, r is the rate of compound interest, P is the principal amount and t is the time.

Thus, amount in compound quarterly, $A=1000(1+\frac{3.7/4}{100} )^{4\times5}$

⇒ $A=1000(1+\frac{3.7}{400} )^{20}$

⇒ $A= 1202.19567617$

Therefore, interest in this compound quarterly rate=1202.19567617-1000=202.19567617

So, the difference in these interests=203.21844013-202.19567617=1.02276396 ≈1.0228

4 0

3 years ago

Read 2 more answers