Answer:
Step-by-step explanation:
To find the distance between any two points, we can use the distance formula:
Our first point, A, is at (1, 1) and our second point, B, is at (-2, 8).
Let's let A(1, 1) be (x₁, y₁) and B(-2, 8) be (x₂, y₂). Substitute this into the distance formula:
Subtract:
Square:
Add:
This cannot be simplified.
So, the distance between the two points is √58 or about 7.6 units.
And we're done!
So... where's my cookie :)?
Answer:
Step-by-step explanation:
Hello! 
because if you multiply numbers with exponents you add the exponents.
Now we've got
.
Sadly it has to be in exponential form. You can substitute 
into the equation if you know a.
For this case we have to take into account the following conversions:
Let's first transform the expression to miles per seconds squared:
Then, we transform the result to miles per minute squared.
We have then:
Answer:
the rate in miles/min^2 is:
Answer:
Step-by-step explanation:
You have shared only one graph, that of a quadratic function with vertex at (0, 0) and an equation based upon y = ax^2, where a is a constant coefficient.
Please go back to the source of your question and describe the other graphs that were given to you.
The graph that shows a straight line is the linear function.
The class is weighted as follows:
60% Regular Tests
10% Final Exam
15% Project
15% Homework
The total weighted points possible for the class are as follows:
(100+100+100+100+100)*.6 + 100*.1 + 100*.15 + 100*.15 = 340
To calculate her individual final weighted grade we plug in her scores for each category and complete the following computation:
(92+83+77+84+82)*.6 + 88*.1 + 95*.15 + 77*.15 = 285.4
So her weighted grade percent would be 285.4/340 = 83.9% which is a B.
