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STALIN [3.7K]
3 years ago
10

Find the total length of fencing required to fence the outer edges of a rectangular park that is 35 meters by 25 meters

Mathematics
1 answer:
kykrilka [37]3 years ago
7 0

Perimeter = 2(length) + 2(width)

                =   2(35)    +   2(25)

                =     70      +     50

                =             120

Answer: 120 meters

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PLEASE I NEED HELP ASAP​
Kruka [31]

Answer:

determine all the other angles amount and that will give you your answer, also find the two 180 degree angles, such as the one flat going left to right and the one at an angle going left to right

Step-by-step explanation:

5 0
3 years ago
What factors multiply to -80 and add to 6
forsale [732]

80 = -1(80), -2(40), -4(20), -5(4),

Total answers include: -81, 79, -42, 16, -9, and 1.

None of them add up to 6!

Are you doing polynomial equations?

If so, you can solve it the hard way.

x^2 + 6x -80 = 0

(x^2 + 6x + 9) - 80 = 9

(x+3)^2 = 89

(x+3) = 9.43

x = 6.43

If you're not doing those then I'm afraid your question has no answer.

Hope that helps!



7 0
3 years ago
If one card is drawn from a deck, find the probability of getting a 4 or a club
Anvisha [2.4K]

Answer:

16/52

Step-by-step explanation:

A 4 or a club4/52 + 13/52 - 1/52 = 16/52 = 4/13f. A 6 or a spade4/52 + 13/52 - 1/52 = 16/52 = 4/13g. A heart or a club13/52 + 13/52 = 26/52 = 1/2h.

8 0
2 years ago
A textbook store sold a combined total of 426 math and sociology textbooks in a week. The number of math textbooks sold was 88 m
SOVA2 [1]
Let m and s be the number of math and sociology books sold respectively.

m=s+88 we are also told that:

m+s=426, using m found above in this equation gives you:

s+88+s=426 combine like terms on left side

2s+88=426  subtract 88 from both sides

2s=338  divide both sides by 2

s=169, since m=s+88

m=169+88=257

So 257 math and 169 sociology textbooks were sold.
8 0
3 years ago
PLEASE HELP ME ASAP
velikii [3]

Answer:

Radius r=0.30m, Velocity, v=36m/s

(a) angular speed w=

r

v

=

0.3

36

=120rad/s

(b) final angular speed w

′

=0

From rotational kinematics w

′

2

−w

2

=2αθ

0−14400=2α×40×2π

⇒α=

160π

−14400

=−28.6rad/s

2

'Distance covered

=40×2πr

=40×2π×0.3=75.39m

5 0
2 years ago
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