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1 year ago

13

What is the consecutve whole numbers of

sqrt{40" align="absmiddle" class="latex-formula">

1 answer:

Inessa [10]1 year ago

3 0

Step-by-step explanation:

$\sqrt{36} < \sqrt{40} < \sqrt{49}$

So sqrt(40) lies between 6 and 7.

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Answer:

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$(h+g)(10) = 3(10)^3-4(10)+1$

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= 3000-39

= 2961

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