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Doss [256]
3 years ago
12

In the equation Y = 8x+ 5 the name for y are

Mathematics
1 answer:
vazorg [7]3 years ago
8 0

Answer:

The equation of any straight line, called a linear equation, can be written as: y = mx + b, where m is the slope of the line and b is the y-intercept. The y-intercept of this line is the value of y at the point where the line crosses the y axis.

Step-by-step explanation:

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How does the volume of an oblique cylinder change if the radius is reduced to 2/9 of its original size and the height is quadrup
vesna_86 [32]
Volume of a cylinder = π r² h

Let us assume the following values:
radius = 9
height = 10

Volume = 3.14 * 9² * 10
            = 3.14 * 81 *10
Volume = 2,543.40

Changes:
radius is reduced to 2/9 of its original size = 9 x 2/9 = 2
height is quadrupled = 10 x 4 = 40

Volume = π r² h
             = 3.14 * 2² * 40
             = 3.14 * 4 * 40
Volume = 502.40

Original volume = 2543.40   V.S.  Volume after change = 502.40

The volume of an oblique cylinder decreased when its radius was decreased to 2/9 of its original size and its height is increased 4 times. 
4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%20%5Csf%20%5Chuge%7B%20question%20%5Chookleftarrow%7D" id="TexFormula1" title=" \sf \huge
BabaBlast [244]

\underline{\bf{Given \:equation:-}}

\\ \sf{:}\dashrightarrow ax^2+by+c=0

\sf Let\:roots\;of\:the\: equation\:be\:\alpha\:and\beta.

\sf We\:know,

\boxed{\sf sum\:of\:roots=\alpha+\beta=\dfrac{-b}{a}}

\boxed{\sf Product\:of\:roots=\alpha\beta=\dfrac{c}{a}}

\underline{\large{\bf Identities\:used:-}}

\boxed{\sf (a+b)^2=a^2+2ab+b^2}

\boxed{\sf (√a)^2=a}

\boxed{\sf \sqrt{a}\sqrt{b}=\sqrt{ab}}

\boxed{\sf \sqrt{\sqrt{a}}=a}

\underline{\bf Final\: Solution:-}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}

\bull\sf Apply\: Squares

\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2= (\sqrt{\alpha})^2+2\sqrt{\alpha}\sqrt{\beta}+(\sqrt{\beta})^2

\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2 \alpha+\beta+2\sqrt{\alpha\beta}

\bull\sf Put\:values

\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2=\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\sqrt{\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}}

\bull\sf Simplify

\\ \sf{:}\dashrightarrow \underline{\boxed{\bf {\sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\sqrt{\dfrac{-b}{a}}+\sqrt{2}\dfrac{c}{a}}}}

\underline{\bf More\: simplification:-}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{-b}}{\sqrt{a}}+\dfrac{c\sqrt{2}}{a}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{a}\sqrt{-b}+c\sqrt{2}}{a}

\underline{\Large{\bf Simplified\: Answer:-}}

\\ \sf{:}\dashrightarrow\underline{\boxed{\bf{ \sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\dfrac{\sqrt{-ab}+c\sqrt{2}}{a}}}}

5 0
2 years ago
Read 2 more answers
From an aeroplane vertically above a straight horizontal plane, the angles of depression of two consecutive kilometres stones on
Airida [17]
You have to build the triangles.

They are such that:
h is the common height
x is the horizontal distance from the plane to one stone
Beta is the angle between x and the  hypotenuse

Then in this triangle: tan(beta) = h / x ......(1)

1 - x is the horizontal distance from the plane to the other stone
alfa is the angle between 1 - x  and h

Then, in this triangle: tan (alfa) = h / [1 -x ] ...... (2)

from (1) , x = h / tan(beta)

Substitute this value in (2)

tan(alfa) = h / { [ 1 - h / tan(beta)] } =>

{ [ 1 - h / tan(beta) ] } tan(alfa) = h

[tan(beta) - h] tan(alfa) = h*tan(beta)

tan(beta)tan(alfa) - htan(alfa) = htan(beta)

h [tan(alfa) + tan(beta) ] = tan(beta) tan (alfa)

h = tan(beta)*tan(alfa) / (t an(alfa)  + tan(beta) )





4 0
4 years ago
Solve for x.<br><br> 23x=49<br><br><br> x=827<br><br> x=23<br><br> x = 2<br><br> x = 3
Lelu [443]

Answer:

x = 49/23

Step-by-step explanation:

23x = 49

=> x = 49/23

I wonder why this option is not one of the options given. Please consider to re-check the options you have given to me.

Thank you!

Hoped this helped.

6 0
2 years ago
Read 2 more answers
HELP ASAP PLZ
WARRIOR [948]
You can use the formula to solve for the y-values in the table. Insert the x-value into the equation: y = 2x - 2

(ex. y = 2(1)-2)

So..

x | y

0 | -2

1 | 0

3 | 4

5 | 8

8 | 14

10 | 18

[First time answering on Brainly so I accidentally commented the answer instead. Don’t know how to delete the comment but anyways, I hope my response helped you!]
4 0
3 years ago
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