<span> y^2 = (3x + 1)^3 / 9x + 2
2*y*(dy/dx)=(9</span>(3x + 1)^2*(9x + 2) -((9*(3x + 1)^3))/ ((9x + 2)^2)
(dy/dx)=(9(3x + 1)^2*(9x + 2) -((9*(3x + 1)^3))/ (2*y*(9x + 2)^2)
(dy/dx)=(9(3x + 1)^2*(6x + 1))/ (2*y*(9x + 2)^2)
answer
A
Answer:

Step-by-step explanation:
We are given with Second-order derivative of function f(x).

We need to find Third-order derivative of the function f(x).

We know that,
f'''(x) = (f''(x))'
So,







Therefore, 
D) 13^(3/5)
This is assuming that the question is asking the √13^3. With the five as the yroot.
Speed = distance / time
speed = 2200/10
speed = 220 miles per hr
Answer:
It's y-values increase at a constant rate as it's x value increases
Step-by-step explanation: